Scheduling based problemDeducing Two Numbers based on their Difference and RatioThe 2 million, er, 20 dollar...
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Scheduling based problem
Deducing Two Numbers based on their Difference and RatioThe 2 million, er, 20 dollar problemAdd a number to each vertex of a triangle such that each edge adds to a perfect squareHexagonal sum fillingEight distinct numbers in the tableIncreasing rows and columnsA simple grid puzzle123456789=1 problemFilling a chessboard with -1, 0 and 1Input/Output Problem #7
$begingroup$
Can you place these numbers into 5 rows of 4 such that each row totals 20?
1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 8, 8, 8
mathematics packing
asked 17 hours ago
JonMark PerryJonMark Perry
20.9k64199
$endgroup$
add a comment |
$begingroup$
Can you place these numbers into 5 rows of 4 such that each row totals 20?
1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 8, 8, 8
mathematics packing
asked 17 hours ago
JonMark PerryJonMark Perry
20.9k64199
$endgroup$
add a comment |
$begingroup$
Can you place these numbers into 5 rows of 4 such that each row totals 20?
1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 8, 8, 8
mathematics packing
asked 17 hours ago
JonMark PerryJonMark Perry
20.9k64199
$endgroup$
Can you place these numbers into 5 rows of 4 such that each row totals 20?
1, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 8, 8, 8
mathematics packing
mathematics packing
asked 17 hours ago
JonMark PerryJonMark Perry
20.9k64199
asked 17 hours ago
JonMark PerryJonMark Perry
20.9k64199
asked 17 hours ago
JonMark PerryJonMark Perry
20.9k64199
asked 17 hours ago
JonMark PerryJonMark Perry
20.9k64199
asked 17 hours ago
JonMark PerryJonMark Perry
20.9k64199
20.9k64199
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Sure.
1,5,6,8
2,4,6,8
3,4,5,8
4,4,5,7
5,5,5,5
Method:
Started from the bigger numbers, and partitioned into 5 parts of 20: {8,8,4}, {8,7,5} and so on.
Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.
With some fiddling, it's also possible to get all the columns to add up to 25:
1,8,6,5
5,4,7,4
5,5,5,5
6,4,2,8
8,4,5,3
And here's a magic square (with duplicates, unavoidably) followed by a row of fives:
1,6,8,5
5,7,4,4
8,5,4,3
6,2,4,8
5,5,5,5
And finally:
4 4 8 4
8 5 4 3
1 5 6 8
7 6 2 5
5 5 5 5
This has
* 20 on all 5 rows
* 20 on all 4 long diagonals
* 25 in all 4 columns
* a magic square on the first 4 rows
answered 17 hours ago
BassBass
31.6k475193
$endgroup$
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
17 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
16 hours ago
$begingroup$
@5202456 Thanks! The original solution seemed to leave an awful lot of "wiggle room" in the pattern, so I wanted to see what I could do with it. I added one more "extra magical" solution after your comment; hopefully I didn't make any mistakes, as the numbers are starting to bounce around in my eyes :-)
$endgroup$
– Bass
14 hours ago
add a comment |
$begingroup$
A bit late to the party and cannot beat the excellent answer from @Bass.
I worked out the number of distinct solutions bearing in mind they can be further permuted by ordering each row and the row sequence. I found
16 distinct solutions
I did this by first finding all the sets of four digits which sum to 20.
There are 17 sets of digits
1 3 8 8
1 4 7 8
1 5 6 8
1 6 6 7
2 3 7 8
2 4 6 8
2 5 5 8
2 5 6 7
3 4 5 8
3 4 6 7
3 5 5 7
3 5 6 6
4 4 4 8
4 4 5 7
4 4 6 6
4 5 5 6
5 5 5 5
I then permuted them for each row so that each digit is used the right number of times.
These are the 16 solutions
1 3 8 8 1 3 8 8 1 3 8 8 1 3 8 8
2 4 6 8 2 5 5 8 2 5 5 8 2 5 6 7
4 4 5 7 4 4 5 7 4 4 5 7 4 4 4 8
4 5 5 6 4 4 6 6 4 5 5 6 4 5 5 6
5 5 5 5 5 5 5 5 4 5 5 6 5 5 5 5
1 4 7 8 1 4 7 8 1 4 7 8 1 4 7 8
2 4 6 8 2 5 5 8 2 5 5 8 2 5 5 8
3 4 5 8 3 4 5 8 3 4 5 8 3 5 6 6
4 5 5 6 4 4 6 6 4 5 5 6 4 4 4 8
5 5 5 5 5 5 5 5 4 5 5 6 5 5 5 5
1 5 6 8 1 5 6 8 1 5 6 8 1 5 6 8
2 3 7 8 2 4 6 8 2 4 6 8 2 5 5 8
4 4 4 8 3 4 5 8 3 5 5 7 3 4 5 8
4 5 5 6 4 4 5 7 4 4 4 8 4 4 5 7
5 5 5 5 5 5 5 5 5 5 5 5 4 5 5 6
1 5 6 8 1 5 6 8 1 5 6 8 1 6 6 7
2 5 5 8 2 5 5 8 2 5 6 7 2 5 5 8
3 4 6 7 3 5 5 7 3 4 5 8 3 4 5 8
4 4 4 8 4 4 4 8 4 4 4 8 4 4 4 8
5 5 5 5 4 5 5 6 5 5 5 5 5 5 5 5
Method:
A computer program written in C.
answered 14 hours ago
Weather VaneWeather Vane
2,708114
$endgroup$
$begingroup$
Nice! FYI I generated the puzzle from row 2 column 4.
$endgroup$
– JonMark Perry
14 hours ago
add a comment |
$begingroup$
This one works
7 3 5 5
8 2 5 5
6 4 5 5
8 6 1 5
8 4 4 4
Method :
Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.
answered 17 hours ago
NarloreNarlore
37615
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Sure.
1,5,6,8
2,4,6,8
3,4,5,8
4,4,5,7
5,5,5,5
Method:
Started from the bigger numbers, and partitioned into 5 parts of 20: {8,8,4}, {8,7,5} and so on.
Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.
With some fiddling, it's also possible to get all the columns to add up to 25:
1,8,6,5
5,4,7,4
5,5,5,5
6,4,2,8
8,4,5,3
And here's a magic square (with duplicates, unavoidably) followed by a row of fives:
1,6,8,5
5,7,4,4
8,5,4,3
6,2,4,8
5,5,5,5
And finally:
4 4 8 4
8 5 4 3
1 5 6 8
7 6 2 5
5 5 5 5
This has
* 20 on all 5 rows
* 20 on all 4 long diagonals
* 25 in all 4 columns
* a magic square on the first 4 rows
answered 17 hours ago
BassBass
31.6k475193
$endgroup$
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
17 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
16 hours ago
$begingroup$
@5202456 Thanks! The original solution seemed to leave an awful lot of "wiggle room" in the pattern, so I wanted to see what I could do with it. I added one more "extra magical" solution after your comment; hopefully I didn't make any mistakes, as the numbers are starting to bounce around in my eyes :-)
$endgroup$
– Bass
14 hours ago
add a comment |
$begingroup$
Sure.
1,5,6,8
2,4,6,8
3,4,5,8
4,4,5,7
5,5,5,5
Method:
Started from the bigger numbers, and partitioned into 5 parts of 20: {8,8,4}, {8,7,5} and so on.
Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.
With some fiddling, it's also possible to get all the columns to add up to 25:
1,8,6,5
5,4,7,4
5,5,5,5
6,4,2,8
8,4,5,3
And here's a magic square (with duplicates, unavoidably) followed by a row of fives:
1,6,8,5
5,7,4,4
8,5,4,3
6,2,4,8
5,5,5,5
And finally:
4 4 8 4
8 5 4 3
1 5 6 8
7 6 2 5
5 5 5 5
This has
* 20 on all 5 rows
* 20 on all 4 long diagonals
* 25 in all 4 columns
* a magic square on the first 4 rows
answered 17 hours ago
BassBass
31.6k475193
$endgroup$
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
17 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
16 hours ago
$begingroup$
@5202456 Thanks! The original solution seemed to leave an awful lot of "wiggle room" in the pattern, so I wanted to see what I could do with it. I added one more "extra magical" solution after your comment; hopefully I didn't make any mistakes, as the numbers are starting to bounce around in my eyes :-)
$endgroup$
– Bass
14 hours ago
add a comment |
$begingroup$
Sure.
1,5,6,8
2,4,6,8
3,4,5,8
4,4,5,7
5,5,5,5
Method:
Started from the bigger numbers, and partitioned into 5 parts of 20: {8,8,4}, {8,7,5} and so on.
Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.
With some fiddling, it's also possible to get all the columns to add up to 25:
1,8,6,5
5,4,7,4
5,5,5,5
6,4,2,8
8,4,5,3
And here's a magic square (with duplicates, unavoidably) followed by a row of fives:
1,6,8,5
5,7,4,4
8,5,4,3
6,2,4,8
5,5,5,5
And finally:
4 4 8 4
8 5 4 3
1 5 6 8
7 6 2 5
5 5 5 5
This has
* 20 on all 5 rows
* 20 on all 4 long diagonals
* 25 in all 4 columns
* a magic square on the first 4 rows
answered 17 hours ago
BassBass
31.6k475193
$endgroup$
Sure.
1,5,6,8
2,4,6,8
3,4,5,8
4,4,5,7
5,5,5,5
Method:
Started from the bigger numbers, and partitioned into 5 parts of 20: {8,8,4}, {8,7,5} and so on.
Then swapped a big number with two smaller ones (with the same sum) on another row until I had 4 numbers on each row.
With some fiddling, it's also possible to get all the columns to add up to 25:
1,8,6,5
5,4,7,4
5,5,5,5
6,4,2,8
8,4,5,3
And here's a magic square (with duplicates, unavoidably) followed by a row of fives:
1,6,8,5
5,7,4,4
8,5,4,3
6,2,4,8
5,5,5,5
And finally:
4 4 8 4
8 5 4 3
1 5 6 8
7 6 2 5
5 5 5 5
This has
* 20 on all 5 rows
* 20 on all 4 long diagonals
* 25 in all 4 columns
* a magic square on the first 4 rows
answered 17 hours ago
BassBass
31.6k475193
edited 14 hours ago
answered 17 hours ago
BassBass
31.6k475193
answered 17 hours ago
BassBass
31.6k475193
answered 17 hours ago
BassBass
31.6k475193
31.6k475193
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
17 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
16 hours ago
$begingroup$
@5202456 Thanks! The original solution seemed to leave an awful lot of "wiggle room" in the pattern, so I wanted to see what I could do with it. I added one more "extra magical" solution after your comment; hopefully I didn't make any mistakes, as the numbers are starting to bounce around in my eyes :-)
$endgroup$
– Bass
14 hours ago
add a comment |
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
17 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
16 hours ago
$begingroup$
@5202456 Thanks! The original solution seemed to leave an awful lot of "wiggle room" in the pattern, so I wanted to see what I could do with it. I added one more "extra magical" solution after your comment; hopefully I didn't make any mistakes, as the numbers are starting to bounce around in my eyes :-)
$endgroup$
– Bass
14 hours ago
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
17 hours ago
$begingroup$
I'm late ! But I have differents rows :D
$endgroup$
– Narlore
17 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
16 hours ago
$begingroup$
I like the way you went on to challenge yourself by finding solutions to your own proposed questions.
$endgroup$
– 5202456
16 hours ago
$begingroup$
@5202456 Thanks! The original solution seemed to leave an awful lot of "wiggle room" in the pattern, so I wanted to see what I could do with it. I added one more "extra magical" solution after your comment; hopefully I didn't make any mistakes, as the numbers are starting to bounce around in my eyes :-)
$endgroup$
– Bass
14 hours ago
$begingroup$
@5202456 Thanks! The original solution seemed to leave an awful lot of "wiggle room" in the pattern, so I wanted to see what I could do with it. I added one more "extra magical" solution after your comment; hopefully I didn't make any mistakes, as the numbers are starting to bounce around in my eyes :-)
$endgroup$
– Bass
14 hours ago
add a comment |
$begingroup$
A bit late to the party and cannot beat the excellent answer from @Bass.
I worked out the number of distinct solutions bearing in mind they can be further permuted by ordering each row and the row sequence. I found
16 distinct solutions
I did this by first finding all the sets of four digits which sum to 20.
There are 17 sets of digits
1 3 8 8
1 4 7 8
1 5 6 8
1 6 6 7
2 3 7 8
2 4 6 8
2 5 5 8
2 5 6 7
3 4 5 8
3 4 6 7
3 5 5 7
3 5 6 6
4 4 4 8
4 4 5 7
4 4 6 6
4 5 5 6
5 5 5 5
I then permuted them for each row so that each digit is used the right number of times.
These are the 16 solutions
1 3 8 8 1 3 8 8 1 3 8 8 1 3 8 8
2 4 6 8 2 5 5 8 2 5 5 8 2 5 6 7
4 4 5 7 4 4 5 7 4 4 5 7 4 4 4 8
4 5 5 6 4 4 6 6 4 5 5 6 4 5 5 6
5 5 5 5 5 5 5 5 4 5 5 6 5 5 5 5
1 4 7 8 1 4 7 8 1 4 7 8 1 4 7 8
2 4 6 8 2 5 5 8 2 5 5 8 2 5 5 8
3 4 5 8 3 4 5 8 3 4 5 8 3 5 6 6
4 5 5 6 4 4 6 6 4 5 5 6 4 4 4 8
5 5 5 5 5 5 5 5 4 5 5 6 5 5 5 5
1 5 6 8 1 5 6 8 1 5 6 8 1 5 6 8
2 3 7 8 2 4 6 8 2 4 6 8 2 5 5 8
4 4 4 8 3 4 5 8 3 5 5 7 3 4 5 8
4 5 5 6 4 4 5 7 4 4 4 8 4 4 5 7
5 5 5 5 5 5 5 5 5 5 5 5 4 5 5 6
1 5 6 8 1 5 6 8 1 5 6 8 1 6 6 7
2 5 5 8 2 5 5 8 2 5 6 7 2 5 5 8
3 4 6 7 3 5 5 7 3 4 5 8 3 4 5 8
4 4 4 8 4 4 4 8 4 4 4 8 4 4 4 8
5 5 5 5 4 5 5 6 5 5 5 5 5 5 5 5
Method:
A computer program written in C.
answered 14 hours ago
Weather VaneWeather Vane
2,708114
$endgroup$
$begingroup$
Nice! FYI I generated the puzzle from row 2 column 4.
$endgroup$
– JonMark Perry
14 hours ago
add a comment |
$begingroup$
A bit late to the party and cannot beat the excellent answer from @Bass.
I worked out the number of distinct solutions bearing in mind they can be further permuted by ordering each row and the row sequence. I found
16 distinct solutions
I did this by first finding all the sets of four digits which sum to 20.
There are 17 sets of digits
1 3 8 8
1 4 7 8
1 5 6 8
1 6 6 7
2 3 7 8
2 4 6 8
2 5 5 8
2 5 6 7
3 4 5 8
3 4 6 7
3 5 5 7
3 5 6 6
4 4 4 8
4 4 5 7
4 4 6 6
4 5 5 6
5 5 5 5
I then permuted them for each row so that each digit is used the right number of times.
These are the 16 solutions
1 3 8 8 1 3 8 8 1 3 8 8 1 3 8 8
2 4 6 8 2 5 5 8 2 5 5 8 2 5 6 7
4 4 5 7 4 4 5 7 4 4 5 7 4 4 4 8
4 5 5 6 4 4 6 6 4 5 5 6 4 5 5 6
5 5 5 5 5 5 5 5 4 5 5 6 5 5 5 5
1 4 7 8 1 4 7 8 1 4 7 8 1 4 7 8
2 4 6 8 2 5 5 8 2 5 5 8 2 5 5 8
3 4 5 8 3 4 5 8 3 4 5 8 3 5 6 6
4 5 5 6 4 4 6 6 4 5 5 6 4 4 4 8
5 5 5 5 5 5 5 5 4 5 5 6 5 5 5 5
1 5 6 8 1 5 6 8 1 5 6 8 1 5 6 8
2 3 7 8 2 4 6 8 2 4 6 8 2 5 5 8
4 4 4 8 3 4 5 8 3 5 5 7 3 4 5 8
4 5 5 6 4 4 5 7 4 4 4 8 4 4 5 7
5 5 5 5 5 5 5 5 5 5 5 5 4 5 5 6
1 5 6 8 1 5 6 8 1 5 6 8 1 6 6 7
2 5 5 8 2 5 5 8 2 5 6 7 2 5 5 8
3 4 6 7 3 5 5 7 3 4 5 8 3 4 5 8
4 4 4 8 4 4 4 8 4 4 4 8 4 4 4 8
5 5 5 5 4 5 5 6 5 5 5 5 5 5 5 5
Method:
A computer program written in C.
answered 14 hours ago
Weather VaneWeather Vane
2,708114
$endgroup$
$begingroup$
Nice! FYI I generated the puzzle from row 2 column 4.
$endgroup$
– JonMark Perry
14 hours ago
add a comment |
$begingroup$
A bit late to the party and cannot beat the excellent answer from @Bass.
I worked out the number of distinct solutions bearing in mind they can be further permuted by ordering each row and the row sequence. I found
16 distinct solutions
I did this by first finding all the sets of four digits which sum to 20.
There are 17 sets of digits
1 3 8 8
1 4 7 8
1 5 6 8
1 6 6 7
2 3 7 8
2 4 6 8
2 5 5 8
2 5 6 7
3 4 5 8
3 4 6 7
3 5 5 7
3 5 6 6
4 4 4 8
4 4 5 7
4 4 6 6
4 5 5 6
5 5 5 5
I then permuted them for each row so that each digit is used the right number of times.
These are the 16 solutions
1 3 8 8 1 3 8 8 1 3 8 8 1 3 8 8
2 4 6 8 2 5 5 8 2 5 5 8 2 5 6 7
4 4 5 7 4 4 5 7 4 4 5 7 4 4 4 8
4 5 5 6 4 4 6 6 4 5 5 6 4 5 5 6
5 5 5 5 5 5 5 5 4 5 5 6 5 5 5 5
1 4 7 8 1 4 7 8 1 4 7 8 1 4 7 8
2 4 6 8 2 5 5 8 2 5 5 8 2 5 5 8
3 4 5 8 3 4 5 8 3 4 5 8 3 5 6 6
4 5 5 6 4 4 6 6 4 5 5 6 4 4 4 8
5 5 5 5 5 5 5 5 4 5 5 6 5 5 5 5
1 5 6 8 1 5 6 8 1 5 6 8 1 5 6 8
2 3 7 8 2 4 6 8 2 4 6 8 2 5 5 8
4 4 4 8 3 4 5 8 3 5 5 7 3 4 5 8
4 5 5 6 4 4 5 7 4 4 4 8 4 4 5 7
5 5 5 5 5 5 5 5 5 5 5 5 4 5 5 6
1 5 6 8 1 5 6 8 1 5 6 8 1 6 6 7
2 5 5 8 2 5 5 8 2 5 6 7 2 5 5 8
3 4 6 7 3 5 5 7 3 4 5 8 3 4 5 8
4 4 4 8 4 4 4 8 4 4 4 8 4 4 4 8
5 5 5 5 4 5 5 6 5 5 5 5 5 5 5 5
Method:
A computer program written in C.
answered 14 hours ago
Weather VaneWeather Vane
2,708114
$endgroup$
A bit late to the party and cannot beat the excellent answer from @Bass.
I worked out the number of distinct solutions bearing in mind they can be further permuted by ordering each row and the row sequence. I found
16 distinct solutions
I did this by first finding all the sets of four digits which sum to 20.
There are 17 sets of digits
1 3 8 8
1 4 7 8
1 5 6 8
1 6 6 7
2 3 7 8
2 4 6 8
2 5 5 8
2 5 6 7
3 4 5 8
3 4 6 7
3 5 5 7
3 5 6 6
4 4 4 8
4 4 5 7
4 4 6 6
4 5 5 6
5 5 5 5
I then permuted them for each row so that each digit is used the right number of times.
These are the 16 solutions
1 3 8 8 1 3 8 8 1 3 8 8 1 3 8 8
2 4 6 8 2 5 5 8 2 5 5 8 2 5 6 7
4 4 5 7 4 4 5 7 4 4 5 7 4 4 4 8
4 5 5 6 4 4 6 6 4 5 5 6 4 5 5 6
5 5 5 5 5 5 5 5 4 5 5 6 5 5 5 5
1 4 7 8 1 4 7 8 1 4 7 8 1 4 7 8
2 4 6 8 2 5 5 8 2 5 5 8 2 5 5 8
3 4 5 8 3 4 5 8 3 4 5 8 3 5 6 6
4 5 5 6 4 4 6 6 4 5 5 6 4 4 4 8
5 5 5 5 5 5 5 5 4 5 5 6 5 5 5 5
1 5 6 8 1 5 6 8 1 5 6 8 1 5 6 8
2 3 7 8 2 4 6 8 2 4 6 8 2 5 5 8
4 4 4 8 3 4 5 8 3 5 5 7 3 4 5 8
4 5 5 6 4 4 5 7 4 4 4 8 4 4 5 7
5 5 5 5 5 5 5 5 5 5 5 5 4 5 5 6
1 5 6 8 1 5 6 8 1 5 6 8 1 6 6 7
2 5 5 8 2 5 5 8 2 5 6 7 2 5 5 8
3 4 6 7 3 5 5 7 3 4 5 8 3 4 5 8
4 4 4 8 4 4 4 8 4 4 4 8 4 4 4 8
5 5 5 5 4 5 5 6 5 5 5 5 5 5 5 5
Method:
A computer program written in C.
answered 14 hours ago
Weather VaneWeather Vane
2,708114
answered 14 hours ago
Weather VaneWeather Vane
2,708114
answered 14 hours ago
Weather VaneWeather Vane
2,708114
answered 14 hours ago
Weather VaneWeather Vane
2,708114
2,708114
$begingroup$
Nice! FYI I generated the puzzle from row 2 column 4.
$endgroup$
– JonMark Perry
14 hours ago
add a comment |
$begingroup$
Nice! FYI I generated the puzzle from row 2 column 4.
$endgroup$
– JonMark Perry
14 hours ago
$begingroup$
Nice! FYI I generated the puzzle from row 2 column 4.
$endgroup$
– JonMark Perry
14 hours ago
$begingroup$
Nice! FYI I generated the puzzle from row 2 column 4.
$endgroup$
– JonMark Perry
14 hours ago
add a comment |
$begingroup$
This one works
7 3 5 5
8 2 5 5
6 4 5 5
8 6 1 5
8 4 4 4
Method :
Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.
answered 17 hours ago
NarloreNarlore
37615
$endgroup$
add a comment |
$begingroup$
This one works
7 3 5 5
8 2 5 5
6 4 5 5
8 6 1 5
8 4 4 4
Method :
Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.
answered 17 hours ago
NarloreNarlore
37615
$endgroup$
add a comment |
$begingroup$
This one works
7 3 5 5
8 2 5 5
6 4 5 5
8 6 1 5
8 4 4 4
Method :
Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.
answered 17 hours ago
NarloreNarlore
37615
$endgroup$
This one works
7 3 5 5
8 2 5 5
6 4 5 5
8 6 1 5
8 4 4 4
Method :
Write randomly the numbers on a piece of paper during 5 min until the solution appears magically.
answered 17 hours ago
NarloreNarlore
37615
edited 17 hours ago
answered 17 hours ago
NarloreNarlore
37615
answered 17 hours ago
NarloreNarlore
37615
answered 17 hours ago
NarloreNarlore
37615
37615
add a comment |
add a comment |
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