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How can I get the count of how many times a string appears in my list?

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1

$begingroup$

I have a list of strings, like so:

{"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss", "kk mm"}

I know WordCounts will return the numbers of every single word, but I want to the word group numbers, i.e., "aa bb" 3 times, and "cc dd" 2 times. How can I do this?

string-manipulation counting

share|improve this question

edited 28 mins ago

m_goldberg

87k872197

asked 3 hours ago

zongxianzongxian

1074

$endgroup$

add a comment | 

1

$begingroup$

I have a list of strings, like so:

{"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss", "kk mm"}

I know WordCounts will return the numbers of every single word, but I want to the word group numbers, i.e., "aa bb" 3 times, and "cc dd" 2 times. How can I do this?

string-manipulation counting

share|improve this question

edited 28 mins ago

m_goldberg

87k872197

asked 3 hours ago

zongxianzongxian

1074

$endgroup$

add a comment | 

$begingroup$

I have a list of strings, like so:

{"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss", "kk mm"}

I know WordCounts will return the numbers of every single word, but I want to the word group numbers, i.e., "aa bb" 3 times, and "cc dd" 2 times. How can I do this?

string-manipulation counting

share|improve this question

edited 28 mins ago

m_goldberg

87k872197

asked 3 hours ago

zongxianzongxian

1074

$endgroup$

{"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss", "kk mm"}

share|improve this question

edited 28 mins ago

m_goldberg

87k872197

asked 3 hours ago

zongxianzongxian

1074

share|improve this question

edited 28 mins ago

m_goldberg

87k872197

asked 3 hours ago

zongxianzongxian

1074

edited 28 mins ago

m_goldberg

87k872197

edited 28 mins ago

m_goldberg

87k872197

asked 3 hours ago

zongxianzongxian

1074

asked 3 hours ago

zongxianzongxian

1074

1 Answer
1

active

oldest

votes

3

$begingroup$

You can try Tally

lst = {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss",   "kk mm"};

Tally[lst]

Edit by m_goldberg

As J.M. says in his comment below, Counts will give the same information as an association.

Counts[data]

<|"aa bb" -> 3, "cc dd" -> 2, "ww ss" -> 1, "ss ss" -> 1, "kk mm" -> 1|>

This is equivalent to

Rule @@@ Tally[data] // Association

share|improve this answer

edited 16 mins ago

m_goldberg

87k872197

answered 2 hours ago

NasserNasser

58k489206

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Counts[] should also work.
  $endgroup$
  – J. M. is computer-less♦
  1 hour ago
  

  
  
  
  

add a comment | 

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3

$begingroup$

You can try Tally

lst = {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss",   "kk mm"};

Tally[lst]

Edit by m_goldberg

As J.M. says in his comment below, Counts will give the same information as an association.

Counts[data]

<|"aa bb" -> 3, "cc dd" -> 2, "ww ss" -> 1, "ss ss" -> 1, "kk mm" -> 1|>

This is equivalent to

Rule @@@ Tally[data] // Association

share|improve this answer

edited 16 mins ago

m_goldberg

87k872197

answered 2 hours ago

NasserNasser

58k489206

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Counts[] should also work.
  $endgroup$
  – J. M. is computer-less♦
  1 hour ago
  

  
  
  
  

add a comment | 

3

$begingroup$

You can try Tally

lst = {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss",   "kk mm"};

Tally[lst]

Edit by m_goldberg

As J.M. says in his comment below, Counts will give the same information as an association.

Counts[data]

<|"aa bb" -> 3, "cc dd" -> 2, "ww ss" -> 1, "ss ss" -> 1, "kk mm" -> 1|>

This is equivalent to

Rule @@@ Tally[data] // Association

share|improve this answer

edited 16 mins ago

m_goldberg

87k872197

answered 2 hours ago

NasserNasser

58k489206

$endgroup$

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Counts[] should also work.
  $endgroup$
  – J. M. is computer-less♦
  1 hour ago
  

  
  
  
  

add a comment | 

$begingroup$

You can try Tally

lst = {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss",   "kk mm"};

Tally[lst]

Edit by m_goldberg

As J.M. says in his comment below, Counts will give the same information as an association.

Counts[data]

<|"aa bb" -> 3, "cc dd" -> 2, "ww ss" -> 1, "ss ss" -> 1, "kk mm" -> 1|>

This is equivalent to

Rule @@@ Tally[data] // Association

share|improve this answer

edited 16 mins ago

m_goldberg

87k872197

answered 2 hours ago

NasserNasser

58k489206

$endgroup$

lst = {"aa bb", "cc dd", "aa bb", "aa bb", "cc dd", "ww ss", "ss ss",   "kk mm"};

Tally[lst]

Counts[data]

Rule @@@ Tally[data] // Association

share|improve this answer

edited 16 mins ago

m_goldberg

87k872197

answered 2 hours ago

NasserNasser

58k489206

edited 16 mins ago

m_goldberg

87k872197

edited 16 mins ago

m_goldberg

87k872197

answered 2 hours ago

NasserNasser

58k489206

answered 2 hours ago

NasserNasser

58k489206