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Prompt for User Input and turn it into an environment variable


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I'm trying to make a script that gives me my current public IP, and asks the user for a new IP that should be declared as an environment variable for ubuntu, however even tho the MASTER variable is working as intended the SLAVE one isn't. here's a minimum sample of my script



#!/bin/bash 
echo $SHELLOPTS
set -o allexport #All variables are auto set to export
MASTER=`ip addr | grep inet | grep 10. | tail -1 | sed 's/^ *//g' | cut -d ' ' -f 2 | sed 's//.*$//g'`
echo Master IP is: $MASTER
echo Insert the new IP:
read input
SLAVE=$input
echo Master IP is: $MASTER
echo Slave IP is: $SLAVE


Even tho the variable is actually printed, it cannot be reused more than once as an environment variable, I have been looking around this problem with no luck, any help will be really appreciated



enter image description here










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  • 3





    If you want the shell variables to continue to exist after the script has finished, you need to source the script, like . scriptname. If you execute it rather than source it, it is run in a subshell and all environmental changes are lost when the subshell exits.

    – John1024
    4 hours ago













  • Or dont use a script at all but a function defined in .bashrc

    – Sergiy Kolodyazhnyy
    4 hours ago


















0















I'm trying to make a script that gives me my current public IP, and asks the user for a new IP that should be declared as an environment variable for ubuntu, however even tho the MASTER variable is working as intended the SLAVE one isn't. here's a minimum sample of my script



#!/bin/bash 
echo $SHELLOPTS
set -o allexport #All variables are auto set to export
MASTER=`ip addr | grep inet | grep 10. | tail -1 | sed 's/^ *//g' | cut -d ' ' -f 2 | sed 's//.*$//g'`
echo Master IP is: $MASTER
echo Insert the new IP:
read input
SLAVE=$input
echo Master IP is: $MASTER
echo Slave IP is: $SLAVE


Even tho the variable is actually printed, it cannot be reused more than once as an environment variable, I have been looking around this problem with no luck, any help will be really appreciated



enter image description here










share|improve this question







New contributor




GoatZero is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 3





    If you want the shell variables to continue to exist after the script has finished, you need to source the script, like . scriptname. If you execute it rather than source it, it is run in a subshell and all environmental changes are lost when the subshell exits.

    – John1024
    4 hours ago













  • Or dont use a script at all but a function defined in .bashrc

    – Sergiy Kolodyazhnyy
    4 hours ago














0












0








0








I'm trying to make a script that gives me my current public IP, and asks the user for a new IP that should be declared as an environment variable for ubuntu, however even tho the MASTER variable is working as intended the SLAVE one isn't. here's a minimum sample of my script



#!/bin/bash 
echo $SHELLOPTS
set -o allexport #All variables are auto set to export
MASTER=`ip addr | grep inet | grep 10. | tail -1 | sed 's/^ *//g' | cut -d ' ' -f 2 | sed 's//.*$//g'`
echo Master IP is: $MASTER
echo Insert the new IP:
read input
SLAVE=$input
echo Master IP is: $MASTER
echo Slave IP is: $SLAVE


Even tho the variable is actually printed, it cannot be reused more than once as an environment variable, I have been looking around this problem with no luck, any help will be really appreciated



enter image description here










share|improve this question







New contributor




GoatZero is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












I'm trying to make a script that gives me my current public IP, and asks the user for a new IP that should be declared as an environment variable for ubuntu, however even tho the MASTER variable is working as intended the SLAVE one isn't. here's a minimum sample of my script



#!/bin/bash 
echo $SHELLOPTS
set -o allexport #All variables are auto set to export
MASTER=`ip addr | grep inet | grep 10. | tail -1 | sed 's/^ *//g' | cut -d ' ' -f 2 | sed 's//.*$//g'`
echo Master IP is: $MASTER
echo Insert the new IP:
read input
SLAVE=$input
echo Master IP is: $MASTER
echo Slave IP is: $SLAVE


Even tho the variable is actually printed, it cannot be reused more than once as an environment variable, I have been looking around this problem with no luck, any help will be really appreciated



enter image description here







command-line bash environment-variables






share|improve this question







New contributor




GoatZero is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




GoatZero is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




GoatZero is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 5 hours ago









GoatZeroGoatZero

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1011




New contributor




GoatZero is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





GoatZero is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






GoatZero is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 3





    If you want the shell variables to continue to exist after the script has finished, you need to source the script, like . scriptname. If you execute it rather than source it, it is run in a subshell and all environmental changes are lost when the subshell exits.

    – John1024
    4 hours ago













  • Or dont use a script at all but a function defined in .bashrc

    – Sergiy Kolodyazhnyy
    4 hours ago














  • 3





    If you want the shell variables to continue to exist after the script has finished, you need to source the script, like . scriptname. If you execute it rather than source it, it is run in a subshell and all environmental changes are lost when the subshell exits.

    – John1024
    4 hours ago













  • Or dont use a script at all but a function defined in .bashrc

    – Sergiy Kolodyazhnyy
    4 hours ago








3




3





If you want the shell variables to continue to exist after the script has finished, you need to source the script, like . scriptname. If you execute it rather than source it, it is run in a subshell and all environmental changes are lost when the subshell exits.

– John1024
4 hours ago







If you want the shell variables to continue to exist after the script has finished, you need to source the script, like . scriptname. If you execute it rather than source it, it is run in a subshell and all environmental changes are lost when the subshell exits.

– John1024
4 hours ago















Or dont use a script at all but a function defined in .bashrc

– Sergiy Kolodyazhnyy
4 hours ago





Or dont use a script at all but a function defined in .bashrc

– Sergiy Kolodyazhnyy
4 hours ago










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