Vertical ranges of Column Plots in 12 Planned maintenance scheduled April 23, 2019 at 23:30...

First paper to introduce the "principal-agent problem"

Why does BitLocker not use RSA?

Is there a spell that can create a permanent fire?

latest version of QGIS fails to edit attribute table of GeoJSON file

Fit odd number of triplets in a measure?

Is this Half-dragon Quaggoth boss monster balanced?

What is a more techy Technical Writer job title that isn't cutesy or confusing?

Can two people see the same photon?

When does a function NOT have an antiderivative?

As a dual citizen, my US passport will expire one day after traveling to the US. Will this work?

How do you write "wild blueberries flavored"?

Does a random sequence of vectors span a Hilbert space?

Should man-made satellites feature an intelligent inverted "cow catcher"?

Does the universe have a fixed centre of mass?

Is the time—manner—place ordering of adverbials an oversimplification?

French equivalents of おしゃれは足元から (Every good outfit starts with the shoes)

2018 MacBook Pro won't let me install macOS High Sierra 10.13 from USB installer

Twin's vs. Twins'

How much damage would a cupful of neutron star matter do to the Earth?

An isoperimetric-type inequality inside a cube

Understanding piped commands in GNU/Linux

Is there a verb for listening stealthily?

How to make triangles with rounded sides and corners? (squircle with 3 sides)

How can I prevent/balance waiting and turtling as a response to cooldown mechanics



Vertical ranges of Column Plots in 12



Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?CustomTicks and small rangesMultiple ranges in one plotFilling between quantile rangesCombine 3D plots with different ranges into oneMake a column of two plotsTransferFunctionModel and BodePlot shows different result between Mathematica and MatlabHow do I control the ranges in plots made with LogLogPlotMultiple plots sharing a single vertical axisVertical and Horizontal Shifts of PlotsConfiguration of `PlotLayout` as “Row”/“Column”












6












$begingroup$


Version 12 includes a new Layout->Column option for ListPlot which aligns multiple plots so they share a single horizontal axis. It seemed really useful at first. But data being compared in this way can have very different vertical scales.



It appears that the new capability always sets the PlotRange of all the data sets to the same value:



d1 = Table[{x, .1 Sin[x]}, {x, 0, 3 Pi, Pi/9}];

d2 = Table[{x, Cos[x]}, {x, 0, 4 Pi, Pi/7}];

ListLinePlot[{d1, d2}, PlotLayout -> "Column",
InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> Automatic]


enter image description here



I have tried what seems reasonable to set the ranges separately:



ListLinePlot[{d1, d2}, PlotLayout -> "Column", 
InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{Automatic, Automatic}, {Automatic, Automatic}}]

ListLinePlot[{d1, d2}, PlotLayout -> "Column",
InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{Automatic, {-.1, .1}}, {Automatic, {-1, 1}}}]


But neither of these work. The first gives the same result, and the second throws an error. Does anyone have any insight into this?



EDIT:



Thank you @Szabolcs. Your solution not only solves the range problem, but permits differing scaling functions. (A cross section of a biased semiconductor junction may want to plot potentials from 0 to 10 volts, but also carrier concentrations from 0 to 1E18 on a log scale.)



d3 = Table[{x, Exp[10 Cos[x]]}, {x, 0, 4 Pi, Pi/100}];
GraphicsColumn[
{
ListLinePlot[d1, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, Automatic}, Frame -> True,
FrameTicks -> {{Automatic, None}, {None, None}},
FrameLabel -> {None, "Linear"}],
ListLinePlot[d3, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, All}, Frame -> True, FrameLabel -> "Log",
ScalingFunctions -> "Log"]
}
]


enter image description here










share|improve this question











$endgroup$












  • $begingroup$
    You can use GraphicsColumn[{...}, Spacings -> {0, -30}] if you need.
    $endgroup$
    – Okkes Dulgerci
    47 mins ago


















6












$begingroup$


Version 12 includes a new Layout->Column option for ListPlot which aligns multiple plots so they share a single horizontal axis. It seemed really useful at first. But data being compared in this way can have very different vertical scales.



It appears that the new capability always sets the PlotRange of all the data sets to the same value:



d1 = Table[{x, .1 Sin[x]}, {x, 0, 3 Pi, Pi/9}];

d2 = Table[{x, Cos[x]}, {x, 0, 4 Pi, Pi/7}];

ListLinePlot[{d1, d2}, PlotLayout -> "Column",
InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> Automatic]


enter image description here



I have tried what seems reasonable to set the ranges separately:



ListLinePlot[{d1, d2}, PlotLayout -> "Column", 
InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{Automatic, Automatic}, {Automatic, Automatic}}]

ListLinePlot[{d1, d2}, PlotLayout -> "Column",
InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{Automatic, {-.1, .1}}, {Automatic, {-1, 1}}}]


But neither of these work. The first gives the same result, and the second throws an error. Does anyone have any insight into this?



EDIT:



Thank you @Szabolcs. Your solution not only solves the range problem, but permits differing scaling functions. (A cross section of a biased semiconductor junction may want to plot potentials from 0 to 10 volts, but also carrier concentrations from 0 to 1E18 on a log scale.)



d3 = Table[{x, Exp[10 Cos[x]]}, {x, 0, 4 Pi, Pi/100}];
GraphicsColumn[
{
ListLinePlot[d1, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, Automatic}, Frame -> True,
FrameTicks -> {{Automatic, None}, {None, None}},
FrameLabel -> {None, "Linear"}],
ListLinePlot[d3, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, All}, Frame -> True, FrameLabel -> "Log",
ScalingFunctions -> "Log"]
}
]


enter image description here










share|improve this question











$endgroup$












  • $begingroup$
    You can use GraphicsColumn[{...}, Spacings -> {0, -30}] if you need.
    $endgroup$
    – Okkes Dulgerci
    47 mins ago
















6












6








6





$begingroup$


Version 12 includes a new Layout->Column option for ListPlot which aligns multiple plots so they share a single horizontal axis. It seemed really useful at first. But data being compared in this way can have very different vertical scales.



It appears that the new capability always sets the PlotRange of all the data sets to the same value:



d1 = Table[{x, .1 Sin[x]}, {x, 0, 3 Pi, Pi/9}];

d2 = Table[{x, Cos[x]}, {x, 0, 4 Pi, Pi/7}];

ListLinePlot[{d1, d2}, PlotLayout -> "Column",
InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> Automatic]


enter image description here



I have tried what seems reasonable to set the ranges separately:



ListLinePlot[{d1, d2}, PlotLayout -> "Column", 
InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{Automatic, Automatic}, {Automatic, Automatic}}]

ListLinePlot[{d1, d2}, PlotLayout -> "Column",
InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{Automatic, {-.1, .1}}, {Automatic, {-1, 1}}}]


But neither of these work. The first gives the same result, and the second throws an error. Does anyone have any insight into this?



EDIT:



Thank you @Szabolcs. Your solution not only solves the range problem, but permits differing scaling functions. (A cross section of a biased semiconductor junction may want to plot potentials from 0 to 10 volts, but also carrier concentrations from 0 to 1E18 on a log scale.)



d3 = Table[{x, Exp[10 Cos[x]]}, {x, 0, 4 Pi, Pi/100}];
GraphicsColumn[
{
ListLinePlot[d1, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, Automatic}, Frame -> True,
FrameTicks -> {{Automatic, None}, {None, None}},
FrameLabel -> {None, "Linear"}],
ListLinePlot[d3, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, All}, Frame -> True, FrameLabel -> "Log",
ScalingFunctions -> "Log"]
}
]


enter image description here










share|improve this question











$endgroup$




Version 12 includes a new Layout->Column option for ListPlot which aligns multiple plots so they share a single horizontal axis. It seemed really useful at first. But data being compared in this way can have very different vertical scales.



It appears that the new capability always sets the PlotRange of all the data sets to the same value:



d1 = Table[{x, .1 Sin[x]}, {x, 0, 3 Pi, Pi/9}];

d2 = Table[{x, Cos[x]}, {x, 0, 4 Pi, Pi/7}];

ListLinePlot[{d1, d2}, PlotLayout -> "Column",
InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> Automatic]


enter image description here



I have tried what seems reasonable to set the ranges separately:



ListLinePlot[{d1, d2}, PlotLayout -> "Column", 
InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{Automatic, Automatic}, {Automatic, Automatic}}]

ListLinePlot[{d1, d2}, PlotLayout -> "Column",
InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{Automatic, {-.1, .1}}, {Automatic, {-1, 1}}}]


But neither of these work. The first gives the same result, and the second throws an error. Does anyone have any insight into this?



EDIT:



Thank you @Szabolcs. Your solution not only solves the range problem, but permits differing scaling functions. (A cross section of a biased semiconductor junction may want to plot potentials from 0 to 10 volts, but also carrier concentrations from 0 to 1E18 on a log scale.)



d3 = Table[{x, Exp[10 Cos[x]]}, {x, 0, 4 Pi, Pi/100}];
GraphicsColumn[
{
ListLinePlot[d1, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, Automatic}, Frame -> True,
FrameTicks -> {{Automatic, None}, {None, None}},
FrameLabel -> {None, "Linear"}],
ListLinePlot[d3, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, All}, Frame -> True, FrameLabel -> "Log",
ScalingFunctions -> "Log"]
}
]


enter image description here







plotting version-12






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 3 hours ago







David Keith

















asked 4 hours ago









David KeithDavid Keith

1,6901314




1,6901314












  • $begingroup$
    You can use GraphicsColumn[{...}, Spacings -> {0, -30}] if you need.
    $endgroup$
    – Okkes Dulgerci
    47 mins ago




















  • $begingroup$
    You can use GraphicsColumn[{...}, Spacings -> {0, -30}] if you need.
    $endgroup$
    – Okkes Dulgerci
    47 mins ago


















$begingroup$
You can use GraphicsColumn[{...}, Spacings -> {0, -30}] if you need.
$endgroup$
– Okkes Dulgerci
47 mins ago






$begingroup$
You can use GraphicsColumn[{...}, Spacings -> {0, -30}] if you need.
$endgroup$
– Okkes Dulgerci
47 mins ago












1 Answer
1






active

oldest

votes


















5












$begingroup$

There is another new feature in M12.0: GraphicsColumn will now align the frames.



You can use this:



d1 = Table[{x, .1 Sin[x]}, {x, 0, 3 Pi, Pi/9}];
d2 = Table[{x, Cos[x]}, {x, 0, 4 Pi, Pi/7}];

GraphicsColumn[
ListLinePlot[#, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, Automatic}, Frame -> True] & /@ {d1, d2}
]


enter image description here



While I did need to set the horizontal range explicitly (so that they match), I did not need to fuss with the ImagePadding to ensure that the frames line up. This saves a lot of work.



Here's what the same looks like in M11.3:



enter image description here



The grids and frames are not quite aligned.






share|improve this answer









$endgroup$













  • $begingroup$
    Thank you, Szabolcs. That works perfectly. I edited my question to comment further.
    $endgroup$
    – David Keith
    3 hours ago












Your Answer








StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f195713%2fvertical-ranges-of-column-plots-in-12%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









5












$begingroup$

There is another new feature in M12.0: GraphicsColumn will now align the frames.



You can use this:



d1 = Table[{x, .1 Sin[x]}, {x, 0, 3 Pi, Pi/9}];
d2 = Table[{x, Cos[x]}, {x, 0, 4 Pi, Pi/7}];

GraphicsColumn[
ListLinePlot[#, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, Automatic}, Frame -> True] & /@ {d1, d2}
]


enter image description here



While I did need to set the horizontal range explicitly (so that they match), I did not need to fuss with the ImagePadding to ensure that the frames line up. This saves a lot of work.



Here's what the same looks like in M11.3:



enter image description here



The grids and frames are not quite aligned.






share|improve this answer









$endgroup$













  • $begingroup$
    Thank you, Szabolcs. That works perfectly. I edited my question to comment further.
    $endgroup$
    – David Keith
    3 hours ago
















5












$begingroup$

There is another new feature in M12.0: GraphicsColumn will now align the frames.



You can use this:



d1 = Table[{x, .1 Sin[x]}, {x, 0, 3 Pi, Pi/9}];
d2 = Table[{x, Cos[x]}, {x, 0, 4 Pi, Pi/7}];

GraphicsColumn[
ListLinePlot[#, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, Automatic}, Frame -> True] & /@ {d1, d2}
]


enter image description here



While I did need to set the horizontal range explicitly (so that they match), I did not need to fuss with the ImagePadding to ensure that the frames line up. This saves a lot of work.



Here's what the same looks like in M11.3:



enter image description here



The grids and frames are not quite aligned.






share|improve this answer









$endgroup$













  • $begingroup$
    Thank you, Szabolcs. That works perfectly. I edited my question to comment further.
    $endgroup$
    – David Keith
    3 hours ago














5












5








5





$begingroup$

There is another new feature in M12.0: GraphicsColumn will now align the frames.



You can use this:



d1 = Table[{x, .1 Sin[x]}, {x, 0, 3 Pi, Pi/9}];
d2 = Table[{x, Cos[x]}, {x, 0, 4 Pi, Pi/7}];

GraphicsColumn[
ListLinePlot[#, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, Automatic}, Frame -> True] & /@ {d1, d2}
]


enter image description here



While I did need to set the horizontal range explicitly (so that they match), I did not need to fuss with the ImagePadding to ensure that the frames line up. This saves a lot of work.



Here's what the same looks like in M11.3:



enter image description here



The grids and frames are not quite aligned.






share|improve this answer









$endgroup$



There is another new feature in M12.0: GraphicsColumn will now align the frames.



You can use this:



d1 = Table[{x, .1 Sin[x]}, {x, 0, 3 Pi, Pi/9}];
d2 = Table[{x, Cos[x]}, {x, 0, 4 Pi, Pi/7}];

GraphicsColumn[
ListLinePlot[#, InterpolationOrder -> 2, GridLines -> Automatic,
PlotRange -> {{0, 4 Pi}, Automatic}, Frame -> True] & /@ {d1, d2}
]


enter image description here



While I did need to set the horizontal range explicitly (so that they match), I did not need to fuss with the ImagePadding to ensure that the frames line up. This saves a lot of work.



Here's what the same looks like in M11.3:



enter image description here



The grids and frames are not quite aligned.







share|improve this answer












share|improve this answer



share|improve this answer










answered 4 hours ago









SzabolcsSzabolcs

165k14450954




165k14450954












  • $begingroup$
    Thank you, Szabolcs. That works perfectly. I edited my question to comment further.
    $endgroup$
    – David Keith
    3 hours ago


















  • $begingroup$
    Thank you, Szabolcs. That works perfectly. I edited my question to comment further.
    $endgroup$
    – David Keith
    3 hours ago
















$begingroup$
Thank you, Szabolcs. That works perfectly. I edited my question to comment further.
$endgroup$
– David Keith
3 hours ago




$begingroup$
Thank you, Szabolcs. That works perfectly. I edited my question to comment further.
$endgroup$
– David Keith
3 hours ago


















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematica Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f195713%2fvertical-ranges-of-column-plots-in-12%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

List of shipwrecks in 1808...

Is there a lightweight tool to crop images quickly?Cropping Images using Command Line Tools OnlyHow to crop...

How do I enter a file or directory with special characters in its name?How to write the path of a folder with...