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Searching extreme points of polyhedron
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
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$begingroup$
In my Uni, my scientific professor asked me to make some researches about the extreme points of polyhedrals. And I did them. I found that there is still no code in public for searching extreme points for polyhedral with n dimensions (n - x's), but polyhedrons are everywhere (CV, game theories, etc.). I wrote a function for this task and made a python library (also there are matrix and array combination maker functions).
All I want is to make this code more optimal and compatible for all python versions (I have some troubles that some times happen when I install it by "pip install lin", but other times no). I want to make the life of people easier and make it more comfortable.
I am asking for you to test this function on your computer and write if you have any bugs, fails or thoughts on how to make it better. I am open to constructive criticism and non-constructive too (it will help to understand if somebody needs it or that is just a waste of time).
All the examples, instructions and code on my GitHub: https://github.com/r4ndompuff/polyhedral_set
import numpy as np
import itertools as it
import math
import re
def permutation(m,n):
return math.factorial(n)/(math.factorial(n-m)*math.factorial(m))
def matrix_combinations(matr,n):
timed = list(map(list, it.combinations(matr, n)))
for i in range(n):
timed[i][i][i] = np.asscalar(timed[i][i][i])
all = np.array(list(timed))
return all
def array_combinations(arr,n):
timed = list(map(list, it.combinations(arr, n)))
for i in range(n):
timed[i][i] = np.asscalar(timed[i][i])
all = np.array(list(timed))
return all
def check_extreme(matr, arr, x, sym_comb, m):
sym_comb = sym_comb.replace(']', '')
sym_comb = sym_comb.replace('[', '')
sym_comb = re.split("[ ,]", sym_comb)
for i in range(m):
td_answer = sum(matr[i]*x)
if sym_comb[i] == '>':
if td_answer <= arr[i]:
return 0
elif sym_comb[i] == '>=':
if td_answer < arr[i]:
return 0
elif sym_comb[i] == '<':
if td_answer >= arr[i]:
return 0
elif sym_comb[i] == '<=':
if td_answer > arr[i]:
return 0
elif sym_comb[i] == '=':
if td_answer != arr[i]:
return 0
elif sym_comb[i] == '!=':
if td_answer == arr[i]:
return 0
else:
return 0
return 1
def extreme_points(m,n,A,b,sym_comb):
# Input
A = np.array(A).reshape(m,n)
b = np.array(b).reshape(m,1)
# Proccess
ans_comb = np.zeros((1,n))
arr_comb = array_combinations(b,n)
matr_comb = matrix_combinations(A,n)
for i in range(int(permutation(n,m))):
if np.linalg.det(matr_comb[i]) != 0:
x = np.linalg.solve(matr_comb[i],arr_comb[i])
ans_comb = np.vstack([ans_comb,x])
ans_comb = np.delete(ans_comb, (0), axis=0)
j = 0
for i in range(len(ans_comb)):
if check_extreme(A, b, ans_comb[j], sym_comb, m):
ans_comb = ans_comb
j = j + 1
else:
ans_comb = np.delete(ans_comb, (j), axis=0)
# Output
return ans_comb
And I am uploading some more tests. https://imgur.com/mjweDyy
python algorithm numpy homework computational-geometry
New contributor
$endgroup$
|
show 2 more comments
$begingroup$
In my Uni, my scientific professor asked me to make some researches about the extreme points of polyhedrals. And I did them. I found that there is still no code in public for searching extreme points for polyhedral with n dimensions (n - x's), but polyhedrons are everywhere (CV, game theories, etc.). I wrote a function for this task and made a python library (also there are matrix and array combination maker functions).
All I want is to make this code more optimal and compatible for all python versions (I have some troubles that some times happen when I install it by "pip install lin", but other times no). I want to make the life of people easier and make it more comfortable.
I am asking for you to test this function on your computer and write if you have any bugs, fails or thoughts on how to make it better. I am open to constructive criticism and non-constructive too (it will help to understand if somebody needs it or that is just a waste of time).
All the examples, instructions and code on my GitHub: https://github.com/r4ndompuff/polyhedral_set
import numpy as np
import itertools as it
import math
import re
def permutation(m,n):
return math.factorial(n)/(math.factorial(n-m)*math.factorial(m))
def matrix_combinations(matr,n):
timed = list(map(list, it.combinations(matr, n)))
for i in range(n):
timed[i][i][i] = np.asscalar(timed[i][i][i])
all = np.array(list(timed))
return all
def array_combinations(arr,n):
timed = list(map(list, it.combinations(arr, n)))
for i in range(n):
timed[i][i] = np.asscalar(timed[i][i])
all = np.array(list(timed))
return all
def check_extreme(matr, arr, x, sym_comb, m):
sym_comb = sym_comb.replace(']', '')
sym_comb = sym_comb.replace('[', '')
sym_comb = re.split("[ ,]", sym_comb)
for i in range(m):
td_answer = sum(matr[i]*x)
if sym_comb[i] == '>':
if td_answer <= arr[i]:
return 0
elif sym_comb[i] == '>=':
if td_answer < arr[i]:
return 0
elif sym_comb[i] == '<':
if td_answer >= arr[i]:
return 0
elif sym_comb[i] == '<=':
if td_answer > arr[i]:
return 0
elif sym_comb[i] == '=':
if td_answer != arr[i]:
return 0
elif sym_comb[i] == '!=':
if td_answer == arr[i]:
return 0
else:
return 0
return 1
def extreme_points(m,n,A,b,sym_comb):
# Input
A = np.array(A).reshape(m,n)
b = np.array(b).reshape(m,1)
# Proccess
ans_comb = np.zeros((1,n))
arr_comb = array_combinations(b,n)
matr_comb = matrix_combinations(A,n)
for i in range(int(permutation(n,m))):
if np.linalg.det(matr_comb[i]) != 0:
x = np.linalg.solve(matr_comb[i],arr_comb[i])
ans_comb = np.vstack([ans_comb,x])
ans_comb = np.delete(ans_comb, (0), axis=0)
j = 0
for i in range(len(ans_comb)):
if check_extreme(A, b, ans_comb[j], sym_comb, m):
ans_comb = ans_comb
j = j + 1
else:
ans_comb = np.delete(ans_comb, (j), axis=0)
# Output
return ans_comb
And I am uploading some more tests. https://imgur.com/mjweDyy
python algorithm numpy homework computational-geometry
New contributor
$endgroup$
$begingroup$
Can you provide some more information on what exactly is going on, from a math standpoint? Is this actually a polyhedron, or a polytope? In how many dimensions? By "extreme", what do you mean? Euclidean norm from (the origin, an arbitrary point)?
$endgroup$
– Reinderien
7 hours ago
$begingroup$
"there is still no code in public for searching extreme points for polyhedral with n dimensions" - I can nearly guarantee that that isn't the case.
$endgroup$
– Reinderien
7 hours ago
1
$begingroup$
@Reinderien I am still in the process of deciphering the question. I have a math background, and I share the mother tongue with OP. My impression is that by extremal points OP means the vertices of a simplex where a certain linear form (defined byA
,b
, and the condition) achieves an extremum. I could be wrong.
$endgroup$
– vnp
5 hours ago
$begingroup$
@vnp That's kind of what I guessed, and if that's the case, linear programming is a quite well-established field already - with some stuff built right into scipy.
$endgroup$
– Reinderien
5 hours ago
$begingroup$
@Reinderien Agreed. Still deciphering.
$endgroup$
– vnp
5 hours ago
|
show 2 more comments
$begingroup$
In my Uni, my scientific professor asked me to make some researches about the extreme points of polyhedrals. And I did them. I found that there is still no code in public for searching extreme points for polyhedral with n dimensions (n - x's), but polyhedrons are everywhere (CV, game theories, etc.). I wrote a function for this task and made a python library (also there are matrix and array combination maker functions).
All I want is to make this code more optimal and compatible for all python versions (I have some troubles that some times happen when I install it by "pip install lin", but other times no). I want to make the life of people easier and make it more comfortable.
I am asking for you to test this function on your computer and write if you have any bugs, fails or thoughts on how to make it better. I am open to constructive criticism and non-constructive too (it will help to understand if somebody needs it or that is just a waste of time).
All the examples, instructions and code on my GitHub: https://github.com/r4ndompuff/polyhedral_set
import numpy as np
import itertools as it
import math
import re
def permutation(m,n):
return math.factorial(n)/(math.factorial(n-m)*math.factorial(m))
def matrix_combinations(matr,n):
timed = list(map(list, it.combinations(matr, n)))
for i in range(n):
timed[i][i][i] = np.asscalar(timed[i][i][i])
all = np.array(list(timed))
return all
def array_combinations(arr,n):
timed = list(map(list, it.combinations(arr, n)))
for i in range(n):
timed[i][i] = np.asscalar(timed[i][i])
all = np.array(list(timed))
return all
def check_extreme(matr, arr, x, sym_comb, m):
sym_comb = sym_comb.replace(']', '')
sym_comb = sym_comb.replace('[', '')
sym_comb = re.split("[ ,]", sym_comb)
for i in range(m):
td_answer = sum(matr[i]*x)
if sym_comb[i] == '>':
if td_answer <= arr[i]:
return 0
elif sym_comb[i] == '>=':
if td_answer < arr[i]:
return 0
elif sym_comb[i] == '<':
if td_answer >= arr[i]:
return 0
elif sym_comb[i] == '<=':
if td_answer > arr[i]:
return 0
elif sym_comb[i] == '=':
if td_answer != arr[i]:
return 0
elif sym_comb[i] == '!=':
if td_answer == arr[i]:
return 0
else:
return 0
return 1
def extreme_points(m,n,A,b,sym_comb):
# Input
A = np.array(A).reshape(m,n)
b = np.array(b).reshape(m,1)
# Proccess
ans_comb = np.zeros((1,n))
arr_comb = array_combinations(b,n)
matr_comb = matrix_combinations(A,n)
for i in range(int(permutation(n,m))):
if np.linalg.det(matr_comb[i]) != 0:
x = np.linalg.solve(matr_comb[i],arr_comb[i])
ans_comb = np.vstack([ans_comb,x])
ans_comb = np.delete(ans_comb, (0), axis=0)
j = 0
for i in range(len(ans_comb)):
if check_extreme(A, b, ans_comb[j], sym_comb, m):
ans_comb = ans_comb
j = j + 1
else:
ans_comb = np.delete(ans_comb, (j), axis=0)
# Output
return ans_comb
And I am uploading some more tests. https://imgur.com/mjweDyy
python algorithm numpy homework computational-geometry
New contributor
$endgroup$
In my Uni, my scientific professor asked me to make some researches about the extreme points of polyhedrals. And I did them. I found that there is still no code in public for searching extreme points for polyhedral with n dimensions (n - x's), but polyhedrons are everywhere (CV, game theories, etc.). I wrote a function for this task and made a python library (also there are matrix and array combination maker functions).
All I want is to make this code more optimal and compatible for all python versions (I have some troubles that some times happen when I install it by "pip install lin", but other times no). I want to make the life of people easier and make it more comfortable.
I am asking for you to test this function on your computer and write if you have any bugs, fails or thoughts on how to make it better. I am open to constructive criticism and non-constructive too (it will help to understand if somebody needs it or that is just a waste of time).
All the examples, instructions and code on my GitHub: https://github.com/r4ndompuff/polyhedral_set
import numpy as np
import itertools as it
import math
import re
def permutation(m,n):
return math.factorial(n)/(math.factorial(n-m)*math.factorial(m))
def matrix_combinations(matr,n):
timed = list(map(list, it.combinations(matr, n)))
for i in range(n):
timed[i][i][i] = np.asscalar(timed[i][i][i])
all = np.array(list(timed))
return all
def array_combinations(arr,n):
timed = list(map(list, it.combinations(arr, n)))
for i in range(n):
timed[i][i] = np.asscalar(timed[i][i])
all = np.array(list(timed))
return all
def check_extreme(matr, arr, x, sym_comb, m):
sym_comb = sym_comb.replace(']', '')
sym_comb = sym_comb.replace('[', '')
sym_comb = re.split("[ ,]", sym_comb)
for i in range(m):
td_answer = sum(matr[i]*x)
if sym_comb[i] == '>':
if td_answer <= arr[i]:
return 0
elif sym_comb[i] == '>=':
if td_answer < arr[i]:
return 0
elif sym_comb[i] == '<':
if td_answer >= arr[i]:
return 0
elif sym_comb[i] == '<=':
if td_answer > arr[i]:
return 0
elif sym_comb[i] == '=':
if td_answer != arr[i]:
return 0
elif sym_comb[i] == '!=':
if td_answer == arr[i]:
return 0
else:
return 0
return 1
def extreme_points(m,n,A,b,sym_comb):
# Input
A = np.array(A).reshape(m,n)
b = np.array(b).reshape(m,1)
# Proccess
ans_comb = np.zeros((1,n))
arr_comb = array_combinations(b,n)
matr_comb = matrix_combinations(A,n)
for i in range(int(permutation(n,m))):
if np.linalg.det(matr_comb[i]) != 0:
x = np.linalg.solve(matr_comb[i],arr_comb[i])
ans_comb = np.vstack([ans_comb,x])
ans_comb = np.delete(ans_comb, (0), axis=0)
j = 0
for i in range(len(ans_comb)):
if check_extreme(A, b, ans_comb[j], sym_comb, m):
ans_comb = ans_comb
j = j + 1
else:
ans_comb = np.delete(ans_comb, (j), axis=0)
# Output
return ans_comb
And I am uploading some more tests. https://imgur.com/mjweDyy
python algorithm numpy homework computational-geometry
python algorithm numpy homework computational-geometry
New contributor
New contributor
edited 3 hours ago
200_success
131k17157422
131k17157422
New contributor
asked 7 hours ago
Andrey LovyaginAndrey Lovyagin
261
261
New contributor
New contributor
$begingroup$
Can you provide some more information on what exactly is going on, from a math standpoint? Is this actually a polyhedron, or a polytope? In how many dimensions? By "extreme", what do you mean? Euclidean norm from (the origin, an arbitrary point)?
$endgroup$
– Reinderien
7 hours ago
$begingroup$
"there is still no code in public for searching extreme points for polyhedral with n dimensions" - I can nearly guarantee that that isn't the case.
$endgroup$
– Reinderien
7 hours ago
1
$begingroup$
@Reinderien I am still in the process of deciphering the question. I have a math background, and I share the mother tongue with OP. My impression is that by extremal points OP means the vertices of a simplex where a certain linear form (defined byA
,b
, and the condition) achieves an extremum. I could be wrong.
$endgroup$
– vnp
5 hours ago
$begingroup$
@vnp That's kind of what I guessed, and if that's the case, linear programming is a quite well-established field already - with some stuff built right into scipy.
$endgroup$
– Reinderien
5 hours ago
$begingroup$
@Reinderien Agreed. Still deciphering.
$endgroup$
– vnp
5 hours ago
|
show 2 more comments
$begingroup$
Can you provide some more information on what exactly is going on, from a math standpoint? Is this actually a polyhedron, or a polytope? In how many dimensions? By "extreme", what do you mean? Euclidean norm from (the origin, an arbitrary point)?
$endgroup$
– Reinderien
7 hours ago
$begingroup$
"there is still no code in public for searching extreme points for polyhedral with n dimensions" - I can nearly guarantee that that isn't the case.
$endgroup$
– Reinderien
7 hours ago
1
$begingroup$
@Reinderien I am still in the process of deciphering the question. I have a math background, and I share the mother tongue with OP. My impression is that by extremal points OP means the vertices of a simplex where a certain linear form (defined byA
,b
, and the condition) achieves an extremum. I could be wrong.
$endgroup$
– vnp
5 hours ago
$begingroup$
@vnp That's kind of what I guessed, and if that's the case, linear programming is a quite well-established field already - with some stuff built right into scipy.
$endgroup$
– Reinderien
5 hours ago
$begingroup$
@Reinderien Agreed. Still deciphering.
$endgroup$
– vnp
5 hours ago
$begingroup$
Can you provide some more information on what exactly is going on, from a math standpoint? Is this actually a polyhedron, or a polytope? In how many dimensions? By "extreme", what do you mean? Euclidean norm from (the origin, an arbitrary point)?
$endgroup$
– Reinderien
7 hours ago
$begingroup$
Can you provide some more information on what exactly is going on, from a math standpoint? Is this actually a polyhedron, or a polytope? In how many dimensions? By "extreme", what do you mean? Euclidean norm from (the origin, an arbitrary point)?
$endgroup$
– Reinderien
7 hours ago
$begingroup$
"there is still no code in public for searching extreme points for polyhedral with n dimensions" - I can nearly guarantee that that isn't the case.
$endgroup$
– Reinderien
7 hours ago
$begingroup$
"there is still no code in public for searching extreme points for polyhedral with n dimensions" - I can nearly guarantee that that isn't the case.
$endgroup$
– Reinderien
7 hours ago
1
1
$begingroup$
@Reinderien I am still in the process of deciphering the question. I have a math background, and I share the mother tongue with OP. My impression is that by extremal points OP means the vertices of a simplex where a certain linear form (defined by
A
, b
, and the condition) achieves an extremum. I could be wrong.$endgroup$
– vnp
5 hours ago
$begingroup$
@Reinderien I am still in the process of deciphering the question. I have a math background, and I share the mother tongue with OP. My impression is that by extremal points OP means the vertices of a simplex where a certain linear form (defined by
A
, b
, and the condition) achieves an extremum. I could be wrong.$endgroup$
– vnp
5 hours ago
$begingroup$
@vnp That's kind of what I guessed, and if that's the case, linear programming is a quite well-established field already - with some stuff built right into scipy.
$endgroup$
– Reinderien
5 hours ago
$begingroup$
@vnp That's kind of what I guessed, and if that's the case, linear programming is a quite well-established field already - with some stuff built right into scipy.
$endgroup$
– Reinderien
5 hours ago
$begingroup$
@Reinderien Agreed. Still deciphering.
$endgroup$
– vnp
5 hours ago
$begingroup$
@Reinderien Agreed. Still deciphering.
$endgroup$
– vnp
5 hours ago
|
show 2 more comments
1 Answer
1
active
oldest
votes
$begingroup$
I created a rudimentary pull request to your GitHub repo. I won't show all of the content here except for the main file:
import numpy as np
import itertools as it
import math
import re
def permutation(m, n):
return math.factorial(n) / (math.factorial(n - m) * math.factorial(m))
def matrix_combinations(matr, n):
timed = list(map(list, it.combinations(matr, n)))
for i in range(n):
timed[i][i][i] = np.asscalar(timed[i][i][i])
return np.array(list(timed))
def array_combinations(arr, n):
timed = list(map(list, it.combinations(arr, n)))
for i in range(n):
timed[i][i] = np.asscalar(timed[i][i])
return np.array(list(timed))
def check_extreme(matr, arr, x, sym_comb, m):
sym_comb = sym_comb.replace(']', '')
sym_comb = sym_comb.replace('[', '')
sym_comb = re.split("[ ,]", sym_comb)
for i in range(m):
td_answer = sum(matr[i] * x)
if sym_comb[i] == '>':
if td_answer <= arr[i]:
return 0
elif sym_comb[i] == '>=':
if td_answer < arr[i]:
return 0
elif sym_comb[i] == '<':
if td_answer >= arr[i]:
return 0
elif sym_comb[i] == '<=':
if td_answer > arr[i]:
return 0
elif sym_comb[i] == '=':
if td_answer != arr[i]:
return 0
elif sym_comb[i] == '!=':
if td_answer == arr[i]:
return 0
else:
return 0
return 1
def extreme_points(m, n, A, b, sym_comb):
# Input
A = np.array(A).reshape(m, n)
b = np.array(b).reshape(m, 1)
# Process
ans_comb = np.zeros((1, n))
arr_comb = array_combinations(b, n)
matr_comb = matrix_combinations(A, n)
for i in range(int(permutation(n, m))):
if np.linalg.det(matr_comb[i]) != 0:
x = np.linalg.solve(matr_comb[i], arr_comb[i])
ans_comb = np.vstack([ans_comb, x])
ans_comb = np.delete(ans_comb, 0, axis=0)
j = 0
for i in range(len(ans_comb)):
if check_extreme(A, b, ans_comb[j], sym_comb, m):
ans_comb = ans_comb
j = j + 1
else:
ans_comb = np.delete(ans_comb, j, axis=0)
# Output
return ans_comb
This is a first cut mainly for PEP8 compliance, and doesn't solve the bigger issue that you should replace 99% of this with a call to scipy. I'll do that separately (I suspect that @vnp is, as well).
$endgroup$
add a comment |
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$begingroup$
I created a rudimentary pull request to your GitHub repo. I won't show all of the content here except for the main file:
import numpy as np
import itertools as it
import math
import re
def permutation(m, n):
return math.factorial(n) / (math.factorial(n - m) * math.factorial(m))
def matrix_combinations(matr, n):
timed = list(map(list, it.combinations(matr, n)))
for i in range(n):
timed[i][i][i] = np.asscalar(timed[i][i][i])
return np.array(list(timed))
def array_combinations(arr, n):
timed = list(map(list, it.combinations(arr, n)))
for i in range(n):
timed[i][i] = np.asscalar(timed[i][i])
return np.array(list(timed))
def check_extreme(matr, arr, x, sym_comb, m):
sym_comb = sym_comb.replace(']', '')
sym_comb = sym_comb.replace('[', '')
sym_comb = re.split("[ ,]", sym_comb)
for i in range(m):
td_answer = sum(matr[i] * x)
if sym_comb[i] == '>':
if td_answer <= arr[i]:
return 0
elif sym_comb[i] == '>=':
if td_answer < arr[i]:
return 0
elif sym_comb[i] == '<':
if td_answer >= arr[i]:
return 0
elif sym_comb[i] == '<=':
if td_answer > arr[i]:
return 0
elif sym_comb[i] == '=':
if td_answer != arr[i]:
return 0
elif sym_comb[i] == '!=':
if td_answer == arr[i]:
return 0
else:
return 0
return 1
def extreme_points(m, n, A, b, sym_comb):
# Input
A = np.array(A).reshape(m, n)
b = np.array(b).reshape(m, 1)
# Process
ans_comb = np.zeros((1, n))
arr_comb = array_combinations(b, n)
matr_comb = matrix_combinations(A, n)
for i in range(int(permutation(n, m))):
if np.linalg.det(matr_comb[i]) != 0:
x = np.linalg.solve(matr_comb[i], arr_comb[i])
ans_comb = np.vstack([ans_comb, x])
ans_comb = np.delete(ans_comb, 0, axis=0)
j = 0
for i in range(len(ans_comb)):
if check_extreme(A, b, ans_comb[j], sym_comb, m):
ans_comb = ans_comb
j = j + 1
else:
ans_comb = np.delete(ans_comb, j, axis=0)
# Output
return ans_comb
This is a first cut mainly for PEP8 compliance, and doesn't solve the bigger issue that you should replace 99% of this with a call to scipy. I'll do that separately (I suspect that @vnp is, as well).
$endgroup$
add a comment |
$begingroup$
I created a rudimentary pull request to your GitHub repo. I won't show all of the content here except for the main file:
import numpy as np
import itertools as it
import math
import re
def permutation(m, n):
return math.factorial(n) / (math.factorial(n - m) * math.factorial(m))
def matrix_combinations(matr, n):
timed = list(map(list, it.combinations(matr, n)))
for i in range(n):
timed[i][i][i] = np.asscalar(timed[i][i][i])
return np.array(list(timed))
def array_combinations(arr, n):
timed = list(map(list, it.combinations(arr, n)))
for i in range(n):
timed[i][i] = np.asscalar(timed[i][i])
return np.array(list(timed))
def check_extreme(matr, arr, x, sym_comb, m):
sym_comb = sym_comb.replace(']', '')
sym_comb = sym_comb.replace('[', '')
sym_comb = re.split("[ ,]", sym_comb)
for i in range(m):
td_answer = sum(matr[i] * x)
if sym_comb[i] == '>':
if td_answer <= arr[i]:
return 0
elif sym_comb[i] == '>=':
if td_answer < arr[i]:
return 0
elif sym_comb[i] == '<':
if td_answer >= arr[i]:
return 0
elif sym_comb[i] == '<=':
if td_answer > arr[i]:
return 0
elif sym_comb[i] == '=':
if td_answer != arr[i]:
return 0
elif sym_comb[i] == '!=':
if td_answer == arr[i]:
return 0
else:
return 0
return 1
def extreme_points(m, n, A, b, sym_comb):
# Input
A = np.array(A).reshape(m, n)
b = np.array(b).reshape(m, 1)
# Process
ans_comb = np.zeros((1, n))
arr_comb = array_combinations(b, n)
matr_comb = matrix_combinations(A, n)
for i in range(int(permutation(n, m))):
if np.linalg.det(matr_comb[i]) != 0:
x = np.linalg.solve(matr_comb[i], arr_comb[i])
ans_comb = np.vstack([ans_comb, x])
ans_comb = np.delete(ans_comb, 0, axis=0)
j = 0
for i in range(len(ans_comb)):
if check_extreme(A, b, ans_comb[j], sym_comb, m):
ans_comb = ans_comb
j = j + 1
else:
ans_comb = np.delete(ans_comb, j, axis=0)
# Output
return ans_comb
This is a first cut mainly for PEP8 compliance, and doesn't solve the bigger issue that you should replace 99% of this with a call to scipy. I'll do that separately (I suspect that @vnp is, as well).
$endgroup$
add a comment |
$begingroup$
I created a rudimentary pull request to your GitHub repo. I won't show all of the content here except for the main file:
import numpy as np
import itertools as it
import math
import re
def permutation(m, n):
return math.factorial(n) / (math.factorial(n - m) * math.factorial(m))
def matrix_combinations(matr, n):
timed = list(map(list, it.combinations(matr, n)))
for i in range(n):
timed[i][i][i] = np.asscalar(timed[i][i][i])
return np.array(list(timed))
def array_combinations(arr, n):
timed = list(map(list, it.combinations(arr, n)))
for i in range(n):
timed[i][i] = np.asscalar(timed[i][i])
return np.array(list(timed))
def check_extreme(matr, arr, x, sym_comb, m):
sym_comb = sym_comb.replace(']', '')
sym_comb = sym_comb.replace('[', '')
sym_comb = re.split("[ ,]", sym_comb)
for i in range(m):
td_answer = sum(matr[i] * x)
if sym_comb[i] == '>':
if td_answer <= arr[i]:
return 0
elif sym_comb[i] == '>=':
if td_answer < arr[i]:
return 0
elif sym_comb[i] == '<':
if td_answer >= arr[i]:
return 0
elif sym_comb[i] == '<=':
if td_answer > arr[i]:
return 0
elif sym_comb[i] == '=':
if td_answer != arr[i]:
return 0
elif sym_comb[i] == '!=':
if td_answer == arr[i]:
return 0
else:
return 0
return 1
def extreme_points(m, n, A, b, sym_comb):
# Input
A = np.array(A).reshape(m, n)
b = np.array(b).reshape(m, 1)
# Process
ans_comb = np.zeros((1, n))
arr_comb = array_combinations(b, n)
matr_comb = matrix_combinations(A, n)
for i in range(int(permutation(n, m))):
if np.linalg.det(matr_comb[i]) != 0:
x = np.linalg.solve(matr_comb[i], arr_comb[i])
ans_comb = np.vstack([ans_comb, x])
ans_comb = np.delete(ans_comb, 0, axis=0)
j = 0
for i in range(len(ans_comb)):
if check_extreme(A, b, ans_comb[j], sym_comb, m):
ans_comb = ans_comb
j = j + 1
else:
ans_comb = np.delete(ans_comb, j, axis=0)
# Output
return ans_comb
This is a first cut mainly for PEP8 compliance, and doesn't solve the bigger issue that you should replace 99% of this with a call to scipy. I'll do that separately (I suspect that @vnp is, as well).
$endgroup$
I created a rudimentary pull request to your GitHub repo. I won't show all of the content here except for the main file:
import numpy as np
import itertools as it
import math
import re
def permutation(m, n):
return math.factorial(n) / (math.factorial(n - m) * math.factorial(m))
def matrix_combinations(matr, n):
timed = list(map(list, it.combinations(matr, n)))
for i in range(n):
timed[i][i][i] = np.asscalar(timed[i][i][i])
return np.array(list(timed))
def array_combinations(arr, n):
timed = list(map(list, it.combinations(arr, n)))
for i in range(n):
timed[i][i] = np.asscalar(timed[i][i])
return np.array(list(timed))
def check_extreme(matr, arr, x, sym_comb, m):
sym_comb = sym_comb.replace(']', '')
sym_comb = sym_comb.replace('[', '')
sym_comb = re.split("[ ,]", sym_comb)
for i in range(m):
td_answer = sum(matr[i] * x)
if sym_comb[i] == '>':
if td_answer <= arr[i]:
return 0
elif sym_comb[i] == '>=':
if td_answer < arr[i]:
return 0
elif sym_comb[i] == '<':
if td_answer >= arr[i]:
return 0
elif sym_comb[i] == '<=':
if td_answer > arr[i]:
return 0
elif sym_comb[i] == '=':
if td_answer != arr[i]:
return 0
elif sym_comb[i] == '!=':
if td_answer == arr[i]:
return 0
else:
return 0
return 1
def extreme_points(m, n, A, b, sym_comb):
# Input
A = np.array(A).reshape(m, n)
b = np.array(b).reshape(m, 1)
# Process
ans_comb = np.zeros((1, n))
arr_comb = array_combinations(b, n)
matr_comb = matrix_combinations(A, n)
for i in range(int(permutation(n, m))):
if np.linalg.det(matr_comb[i]) != 0:
x = np.linalg.solve(matr_comb[i], arr_comb[i])
ans_comb = np.vstack([ans_comb, x])
ans_comb = np.delete(ans_comb, 0, axis=0)
j = 0
for i in range(len(ans_comb)):
if check_extreme(A, b, ans_comb[j], sym_comb, m):
ans_comb = ans_comb
j = j + 1
else:
ans_comb = np.delete(ans_comb, j, axis=0)
# Output
return ans_comb
This is a first cut mainly for PEP8 compliance, and doesn't solve the bigger issue that you should replace 99% of this with a call to scipy. I'll do that separately (I suspect that @vnp is, as well).
answered 5 hours ago
ReinderienReinderien
5,494928
5,494928
add a comment |
add a comment |
Andrey Lovyagin is a new contributor. Be nice, and check out our Code of Conduct.
Andrey Lovyagin is a new contributor. Be nice, and check out our Code of Conduct.
Andrey Lovyagin is a new contributor. Be nice, and check out our Code of Conduct.
Andrey Lovyagin is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Can you provide some more information on what exactly is going on, from a math standpoint? Is this actually a polyhedron, or a polytope? In how many dimensions? By "extreme", what do you mean? Euclidean norm from (the origin, an arbitrary point)?
$endgroup$
– Reinderien
7 hours ago
$begingroup$
"there is still no code in public for searching extreme points for polyhedral with n dimensions" - I can nearly guarantee that that isn't the case.
$endgroup$
– Reinderien
7 hours ago
1
$begingroup$
@Reinderien I am still in the process of deciphering the question. I have a math background, and I share the mother tongue with OP. My impression is that by extremal points OP means the vertices of a simplex where a certain linear form (defined by
A
,b
, and the condition) achieves an extremum. I could be wrong.$endgroup$
– vnp
5 hours ago
$begingroup$
@vnp That's kind of what I guessed, and if that's the case, linear programming is a quite well-established field already - with some stuff built right into scipy.
$endgroup$
– Reinderien
5 hours ago
$begingroup$
@Reinderien Agreed. Still deciphering.
$endgroup$
– vnp
5 hours ago