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Compilation of a 2d array and a 1d array
The Next CEO of Stack OverflowInserting points along a linear interval between adjacent coordinates in an arrayDynamic arrays and lists with compile (Append, Linked lists etc.)Numbering indices / array element positions while creating an array (using 3 argument form)Lattice model array for distribution of energyinsert elements into 2 D arraySpeed differences between Table, Replace, Array, Map, and AssociationMapUsing a set of indices to select a subset of an array2D array summation operationsEfficiency in array element replacementSelect an element from each matrix row/column specified by a vector
$begingroup$
With a list say {{x1,y1},{x2,y2}…} and a list {z1}, what is the best way to create a list {{x1,y1,z1},{x2,y2,z1},{x3,y3,z1}…}
list-manipulation array
asked 3 hours ago
tombom21tombom21
83
$endgroup$
add a comment |
$begingroup$
With a list say {{x1,y1},{x2,y2}…} and a list {z1}, what is the best way to create a list {{x1,y1,z1},{x2,y2,z1},{x3,y3,z1}…}
list-manipulation array
asked 3 hours ago
tombom21tombom21
83
$endgroup$
add a comment |
$begingroup$
With a list say {{x1,y1},{x2,y2}…} and a list {z1}, what is the best way to create a list {{x1,y1,z1},{x2,y2,z1},{x3,y3,z1}…}
list-manipulation array
asked 3 hours ago
tombom21tombom21
83
$endgroup$
With a list say {{x1,y1},{x2,y2}…} and a list {z1}, what is the best way to create a list {{x1,y1,z1},{x2,y2,z1},{x3,y3,z1}…}
list-manipulation array
list-manipulation array
asked 3 hours ago
tombom21tombom21
83
asked 3 hours ago
tombom21tombom21
83
asked 3 hours ago
tombom21tombom21
83
asked 3 hours ago
tombom21tombom21
83
asked 3 hours ago
tombom21tombom21
83
83
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
You can use PadRight:
PadRight[
{{x1, y1}, {x2, y2}},
{Automatic, 3},
z1
]
{{x1, y1, z1}, {x2, y2, z1}}
Or ArrayPad:
ArrayPad[
{{x1, y1}, {x2, y2}, {x3, y3}},
{{0,0},{0,1}},
z1
]
{{x1, y1, z1}, {x2, y2, z1}, {x3, y3, z1}}
answered 3 hours ago
Carl WollCarl Woll
72.2k395186
$endgroup$
add a comment |
$begingroup$
n = 1000000;
a = RandomReal[{-1, 1}, {n, 2}];
b = ConstantArray[0., 1];
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First
0.016
answered 3 hours ago
Henrik SchumacherHenrik Schumacher
58.7k581162
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can use PadRight:
PadRight[
{{x1, y1}, {x2, y2}},
{Automatic, 3},
z1
]
{{x1, y1, z1}, {x2, y2, z1}}
Or ArrayPad:
ArrayPad[
{{x1, y1}, {x2, y2}, {x3, y3}},
{{0,0},{0,1}},
z1
]
{{x1, y1, z1}, {x2, y2, z1}, {x3, y3, z1}}
answered 3 hours ago
Carl WollCarl Woll
72.2k395186
$endgroup$
add a comment |
$begingroup$
You can use PadRight:
PadRight[
{{x1, y1}, {x2, y2}},
{Automatic, 3},
z1
]
{{x1, y1, z1}, {x2, y2, z1}}
Or ArrayPad:
ArrayPad[
{{x1, y1}, {x2, y2}, {x3, y3}},
{{0,0},{0,1}},
z1
]
{{x1, y1, z1}, {x2, y2, z1}, {x3, y3, z1}}
answered 3 hours ago
Carl WollCarl Woll
72.2k395186
$endgroup$
add a comment |
$begingroup$
You can use PadRight:
PadRight[
{{x1, y1}, {x2, y2}},
{Automatic, 3},
z1
]
{{x1, y1, z1}, {x2, y2, z1}}
Or ArrayPad:
ArrayPad[
{{x1, y1}, {x2, y2}, {x3, y3}},
{{0,0},{0,1}},
z1
]
{{x1, y1, z1}, {x2, y2, z1}, {x3, y3, z1}}
answered 3 hours ago
Carl WollCarl Woll
72.2k395186
$endgroup$
You can use PadRight:
PadRight[
{{x1, y1}, {x2, y2}},
{Automatic, 3},
z1
]
{{x1, y1, z1}, {x2, y2, z1}}
Or ArrayPad:
ArrayPad[
{{x1, y1}, {x2, y2}, {x3, y3}},
{{0,0},{0,1}},
z1
]
{{x1, y1, z1}, {x2, y2, z1}, {x3, y3, z1}}
answered 3 hours ago
Carl WollCarl Woll
72.2k395186
answered 3 hours ago
Carl WollCarl Woll
72.2k395186
answered 3 hours ago
Carl WollCarl Woll
72.2k395186
answered 3 hours ago
Carl WollCarl Woll
72.2k395186
72.2k395186
add a comment |
add a comment |
$begingroup$
n = 1000000;
a = RandomReal[{-1, 1}, {n, 2}];
b = ConstantArray[0., 1];
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First
0.016
answered 3 hours ago
Henrik SchumacherHenrik Schumacher
58.7k581162
$endgroup$
add a comment |
$begingroup$
n = 1000000;
a = RandomReal[{-1, 1}, {n, 2}];
b = ConstantArray[0., 1];
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First
0.016
answered 3 hours ago
Henrik SchumacherHenrik Schumacher
58.7k581162
$endgroup$
add a comment |
$begingroup$
n = 1000000;
a = RandomReal[{-1, 1}, {n, 2}];
b = ConstantArray[0., 1];
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First
0.016
answered 3 hours ago
Henrik SchumacherHenrik Schumacher
58.7k581162
$endgroup$
n = 1000000;
a = RandomReal[{-1, 1}, {n, 2}];
b = ConstantArray[0., 1];
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First
0.016
answered 3 hours ago
Henrik SchumacherHenrik Schumacher
58.7k581162
answered 3 hours ago
Henrik SchumacherHenrik Schumacher
58.7k581162
answered 3 hours ago
Henrik SchumacherHenrik Schumacher
58.7k581162
answered 3 hours ago
Henrik SchumacherHenrik Schumacher
58.7k581162
58.7k581162
add a comment |
add a comment |
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