show this identity with trigometricA cubed trigonometric identity?Trigonometric Double Angle proofHow to...
Is Gradient Descent central to every optimizer?
Why does Captain Marvel assume the planet where she lands would recognize her credentials?
Should QA ask requirements to developers?
What are the best books to study Neural Networks from a purely mathematical perspective?
Could you please stop shuffling the deck and play already?
Can someone explain what is being said here in color publishing in the American Mathematical Monthly?
String reversal in Python
BitNot does not flip bits in the way I expected
How do anti-virus programs start at Windows boot?
Is it true that real estate prices mainly go up?
How could our ancestors have domesticated a solitary predator?
Why would a jet engine that runs at temps excess of 2000°C burn when it crashes?
MTG: Can I kill an opponent in response to lethal activated abilities, and not take the damage?
"One can do his homework in the library"
Do Bugbears' arms literally get longer when it's their turn?
How much stiffer are 23c tires over 28c?
Could a cubesat be propelled to the moon?
Can you reject a postdoc offer after the PI has paid a large sum for flights/accommodation for your visit?
Accountant/ lawyer will not return my call
A question on the ultrafilter number
How does airport security verify that you can carry a battery bank over 100 Wh?
How do I deal with a powergamer in a game full of beginners in a school club?
Replacing Windows 7 security updates with anti-virus?
Solving "Resistance between two nodes on a grid" problem in Mathematica
show this identity with trigometric
A cubed trigonometric identity?Trigonometric Double Angle proofHow to properly use this trigonometric identity?How prove this idenity this $mv-3nu=m-3u$ with unit circleTough Trigonometric Identity ProblemGeometric meaning of a conditional trigonometric identityHow many points to prove a trigonometric identity?Solution for the trigonometric-linear functionHow do I write $csc$ and $tan$ in terms of $sin$ and $cos$?Simplifying a Trigonometric Expression with Sum Difference Identity
$begingroup$
I sent a post earlier. Follow is an original problem. I got an error identity from a previous calculation error. Now there should be no problem.
Problem::
let $x,yin (0,dfrac{pi}{2})$. show that
$$dfrac{sin{(x+y)}tan{x}-cos{(x+y)}}{sin{(x+y)}tan{y}-cos{(x+y)}}=dfrac{cos{(2x+y)}cos{y}}{cos{(x+2y)}cos{x}}$$
This identity comes from the fact that I deal with a geometric problem and use trigonometric functions to calculate an identity that needs to be proved.Thanks
trigonometry
asked 3 hours ago
function sugfunction sug
3381438
$endgroup$
add a comment |
$begingroup$
I sent a post earlier. Follow is an original problem. I got an error identity from a previous calculation error. Now there should be no problem.
Problem::
let $x,yin (0,dfrac{pi}{2})$. show that
$$dfrac{sin{(x+y)}tan{x}-cos{(x+y)}}{sin{(x+y)}tan{y}-cos{(x+y)}}=dfrac{cos{(2x+y)}cos{y}}{cos{(x+2y)}cos{x}}$$
This identity comes from the fact that I deal with a geometric problem and use trigonometric functions to calculate an identity that needs to be proved.Thanks
trigonometry
asked 3 hours ago
function sugfunction sug
3381438
$endgroup$
1
$begingroup$
This version seems to be true. :) (Note: You should not delete a question that has received an answer. Doing so is inconsiderate to the answerer who has taken valuable time to respond to your question.)
$endgroup$
– Blue
3 hours ago
add a comment |
$begingroup$
I sent a post earlier. Follow is an original problem. I got an error identity from a previous calculation error. Now there should be no problem.
Problem::
let $x,yin (0,dfrac{pi}{2})$. show that
$$dfrac{sin{(x+y)}tan{x}-cos{(x+y)}}{sin{(x+y)}tan{y}-cos{(x+y)}}=dfrac{cos{(2x+y)}cos{y}}{cos{(x+2y)}cos{x}}$$
This identity comes from the fact that I deal with a geometric problem and use trigonometric functions to calculate an identity that needs to be proved.Thanks
trigonometry
asked 3 hours ago
function sugfunction sug
3381438
$endgroup$
I sent a post earlier. Follow is an original problem. I got an error identity from a previous calculation error. Now there should be no problem.
Problem::
let $x,yin (0,dfrac{pi}{2})$. show that
$$dfrac{sin{(x+y)}tan{x}-cos{(x+y)}}{sin{(x+y)}tan{y}-cos{(x+y)}}=dfrac{cos{(2x+y)}cos{y}}{cos{(x+2y)}cos{x}}$$
This identity comes from the fact that I deal with a geometric problem and use trigonometric functions to calculate an identity that needs to be proved.Thanks
trigonometry
trigonometry
asked 3 hours ago
function sugfunction sug
3381438
asked 3 hours ago
function sugfunction sug
3381438
asked 3 hours ago
function sugfunction sug
3381438
asked 3 hours ago
function sugfunction sug
3381438
asked 3 hours ago
function sugfunction sug
3381438
3381438
1
$begingroup$
This version seems to be true. :) (Note: You should not delete a question that has received an answer. Doing so is inconsiderate to the answerer who has taken valuable time to respond to your question.)
$endgroup$
– Blue
3 hours ago
add a comment |
1
$begingroup$
This version seems to be true. :) (Note: You should not delete a question that has received an answer. Doing so is inconsiderate to the answerer who has taken valuable time to respond to your question.)
$endgroup$
– Blue
3 hours ago
1
1
$begingroup$
This version seems to be true. :) (Note: You should not delete a question that has received an answer. Doing so is inconsiderate to the answerer who has taken valuable time to respond to your question.)
$endgroup$
– Blue
3 hours ago
$begingroup$
This version seems to be true. :) (Note: You should not delete a question that has received an answer. Doing so is inconsiderate to the answerer who has taken valuable time to respond to your question.)
$endgroup$
– Blue
3 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Hint:
$$begin{align}
sin(x+y)tan x - cos(x+y) &= phantom{-}frac{1}{cos x}left(;sin(x+y) sin x - cos(x+y)cos x;right) \[4pt]
&= -frac1{cos x}cosleft((x+y)+xright) \[4pt]
&= -frac1{cos x}cosleft(2x+yright)
end{align}$$
answered 3 hours ago
BlueBlue
49k870156
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3145988%2fshow-this-identity-with-trigometric%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Hint:
$$begin{align}
sin(x+y)tan x - cos(x+y) &= phantom{-}frac{1}{cos x}left(;sin(x+y) sin x - cos(x+y)cos x;right) \[4pt]
&= -frac1{cos x}cosleft((x+y)+xright) \[4pt]
&= -frac1{cos x}cosleft(2x+yright)
end{align}$$
answered 3 hours ago
BlueBlue
49k870156
$endgroup$
add a comment |
$begingroup$
Hint:
$$begin{align}
sin(x+y)tan x - cos(x+y) &= phantom{-}frac{1}{cos x}left(;sin(x+y) sin x - cos(x+y)cos x;right) \[4pt]
&= -frac1{cos x}cosleft((x+y)+xright) \[4pt]
&= -frac1{cos x}cosleft(2x+yright)
end{align}$$
answered 3 hours ago
BlueBlue
49k870156
$endgroup$
add a comment |
$begingroup$
Hint:
$$begin{align}
sin(x+y)tan x - cos(x+y) &= phantom{-}frac{1}{cos x}left(;sin(x+y) sin x - cos(x+y)cos x;right) \[4pt]
&= -frac1{cos x}cosleft((x+y)+xright) \[4pt]
&= -frac1{cos x}cosleft(2x+yright)
end{align}$$
answered 3 hours ago
BlueBlue
49k870156
$endgroup$
Hint:
$$begin{align}
sin(x+y)tan x - cos(x+y) &= phantom{-}frac{1}{cos x}left(;sin(x+y) sin x - cos(x+y)cos x;right) \[4pt]
&= -frac1{cos x}cosleft((x+y)+xright) \[4pt]
&= -frac1{cos x}cosleft(2x+yright)
end{align}$$
answered 3 hours ago
BlueBlue
49k870156
answered 3 hours ago
BlueBlue
49k870156
answered 3 hours ago
BlueBlue
49k870156
answered 3 hours ago
BlueBlue
49k870156
49k870156
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3145988%2fshow-this-identity-with-trigometric%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
$begingroup$
This version seems to be true. :) (Note: You should not delete a question that has received an answer. Doing so is inconsiderate to the answerer who has taken valuable time to respond to your question.)
$endgroup$
– Blue
3 hours ago