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Asymptote: 3d graph over a disc

3

Is there a straightforward way to draw a 3D graph over a disc domain? Say
z=x^2-y^2 for x^2+y^2<1.

[I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]

graphs asymptote

share|improve this question

asked 3 hours ago

Anton PetruninAnton Petrunin

532313

add a comment | 

3

Is there a straightforward way to draw a 3D graph over a disc domain? Say
z=x^2-y^2 for x^2+y^2<1.

[I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]

graphs asymptote

share|improve this question

asked 3 hours ago

Anton PetruninAnton Petrunin

532313

add a comment | 

Is there a straightforward way to draw a 3D graph over a disc domain? Say
z=x^2-y^2 for x^2+y^2<1.

[I just started to use asymptote; this page explained me how to do it for a rectangular domain. I hope it is an easy question.]

graphs asymptote

share|improve this question

asked 3 hours ago

Anton PetruninAnton Petrunin

532313

share|improve this question

asked 3 hours ago

Anton PetruninAnton Petrunin

532313

share|improve this question

asked 3 hours ago

Anton PetruninAnton Petrunin

532313

asked 3 hours ago

Anton PetruninAnton Petrunin

532313

asked 3 hours ago

Anton PetruninAnton Petrunin

532313

1 Answer
1

active

oldest

votes

3

One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).

documentclass[variwidth,border=3.14mm]{standalone}

usepackage{asypictureB}

begin{document}

begin{asypicture}{name=discgraph}

 usepackage("mathrsfs");

 import graph3;

 import solids;

 import interpolate;



 settings.outformat="pdf";





 size(500); 



 defaultpen(0.5mm);

 pen darkgreen=rgb(0,138/255,122/255);



 draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);

 draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);

 draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);







 //function: call the radial coordinate r=t.x and the angle phi=t.y

 triple f(pair t) {

 return ((t.x)*cos(t.y), (t.x)*sin(t.y),

 ((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);

 }



 surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,

          usplinetype=new splinetype[] {notaknot,notaknot,monotonic},

          vsplinetype=Spline);

 pen p=rgb(0,0,.7); 

 draw(s,lightolive+white);

end{asypicture} 

end{document}

share|improve this answer

answered 2 hours ago

marmotmarmot

113k5145275

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?
  
  – Anton Petrunin
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?
  
  – Marian G.
  1 hour ago
  

  
  
  
  

add a comment | 

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3

One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).

documentclass[variwidth,border=3.14mm]{standalone}

usepackage{asypictureB}

begin{document}

begin{asypicture}{name=discgraph}

 usepackage("mathrsfs");

 import graph3;

 import solids;

 import interpolate;



 settings.outformat="pdf";





 size(500); 



 defaultpen(0.5mm);

 pen darkgreen=rgb(0,138/255,122/255);



 draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);

 draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);

 draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);







 //function: call the radial coordinate r=t.x and the angle phi=t.y

 triple f(pair t) {

 return ((t.x)*cos(t.y), (t.x)*sin(t.y),

 ((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);

 }



 surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,

          usplinetype=new splinetype[] {notaknot,notaknot,monotonic},

          vsplinetype=Spline);

 pen p=rgb(0,0,.7); 

 draw(s,lightolive+white);

end{asypicture} 

end{document}

share|improve this answer

answered 2 hours ago

marmotmarmot

113k5145275

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?
  
  – Anton Petrunin
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?
  
  – Marian G.
  1 hour ago
  

  
  
  
  

add a comment | 

3

One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).

documentclass[variwidth,border=3.14mm]{standalone}

usepackage{asypictureB}

begin{document}

begin{asypicture}{name=discgraph}

 usepackage("mathrsfs");

 import graph3;

 import solids;

 import interpolate;



 settings.outformat="pdf";





 size(500); 



 defaultpen(0.5mm);

 pen darkgreen=rgb(0,138/255,122/255);



 draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);

 draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);

 draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);







 //function: call the radial coordinate r=t.x and the angle phi=t.y

 triple f(pair t) {

 return ((t.x)*cos(t.y), (t.x)*sin(t.y),

 ((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);

 }



 surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,

          usplinetype=new splinetype[] {notaknot,notaknot,monotonic},

          vsplinetype=Spline);

 pen p=rgb(0,0,.7); 

 draw(s,lightolive+white);

end{asypicture} 

end{document}

share|improve this answer

answered 2 hours ago

marmotmarmot

113k5145275

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you, but is there a direct way to make a condition x^2+y^2<1 for the arguments?
  
  – Anton Petrunin
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @marmot: The x-axis near origin should be hidden from the given point of view. Is there any way to improve this issue? E.g., by setting some samples-option?
  
  – Marian G.
  1 hour ago
  

  
  
  
  

add a comment | 

One way to make sure that x^2+y^2<1 is to use polar coordinates. Then x=r cos(phi) and y=r sin(phi).

documentclass[variwidth,border=3.14mm]{standalone}

usepackage{asypictureB}

begin{document}

begin{asypicture}{name=discgraph}

 usepackage("mathrsfs");

 import graph3;

 import solids;

 import interpolate;



 settings.outformat="pdf";





 size(500); 



 defaultpen(0.5mm);

 pen darkgreen=rgb(0,138/255,122/255);



 draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);

 draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);

 draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);







 //function: call the radial coordinate r=t.x and the angle phi=t.y

 triple f(pair t) {

 return ((t.x)*cos(t.y), (t.x)*sin(t.y),

 ((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);

 }



 surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,

          usplinetype=new splinetype[] {notaknot,notaknot,monotonic},

          vsplinetype=Spline);

 pen p=rgb(0,0,.7); 

 draw(s,lightolive+white);

end{asypicture} 

end{document}

share|improve this answer

answered 2 hours ago

marmotmarmot

113k5145275

documentclass[variwidth,border=3.14mm]{standalone}

usepackage{asypictureB}

begin{document}

begin{asypicture}{name=discgraph}

 usepackage("mathrsfs");

 import graph3;

 import solids;

 import interpolate;



 settings.outformat="pdf";





 size(500); 



 defaultpen(0.5mm);

 pen darkgreen=rgb(0,138/255,122/255);



 draw(Label("$x$",1),(0,0,0)--(1.2,0,0),darkgreen,Arrow3);

 draw(Label("$y$",1),(0,0,0)--(0,1.2,0),darkgreen,Arrow3);

 draw(Label("$f(x,y)$",1),(0,0,0)--(0,0,0.6),darkgreen,Arrow3);







 //function: call the radial coordinate r=t.x and the angle phi=t.y

 triple f(pair t) {

 return ((t.x)*cos(t.y), (t.x)*sin(t.y),

 ((t.x)*cos(t.y))^2-((t.x)*sin(t.y))^2);

 }



 surface s=surface(f,(0,1),(0.49,2.5*pi),32,16,

          usplinetype=new splinetype[] {notaknot,notaknot,monotonic},

          vsplinetype=Spline);

 pen p=rgb(0,0,.7); 

 draw(s,lightolive+white);

end{asypicture} 

end{document}

share|improve this answer

answered 2 hours ago

marmotmarmot

113k5145275

answered 2 hours ago

marmotmarmot

113k5145275

answered 2 hours ago

marmotmarmot

113k5145275