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How to get regions to plot as graphics

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How to get regions to plot as graphics



The Next CEO of Stack OverflowHow to get 2D graphics into 3D without background?Restrict MousePosition to specific Graphics objectCan't plot rotated regionOpacity function applied to Graphics ObjectsHow to make Inset graphics maintain relative sizes when combinedHow to apply a color gradient to a Rectangle primitive?How to plot the difference between two regions?Zoom into RegionPlot of a region made with RegionDifference/RegionUnionWhy this “is not a correctly specified region”?FacialFeatures is not a Graphics primitive or directive












2












$begingroup$


I want to put an anulus in my graphics object. How can I format a region difference into a graphics primitive?



a=1;b=5;
Region[RegionDifference[Disk[{0,0},b],Disk[{0,0},a]]] (*works*)
Graphics[{Rectangle[{5,5}], Blue,Rectangle[{-5,-5}],RegionDifference[Disk[{0,0},b],Disk[{0,0},a]]}](*doesn't work*)
Head[RegionDifference[Disk[{0,0},b],Disk[{0,0},a]]] (* wrong object type *)
Head[Disk[]]









share|improve this question









$endgroup$








  • 4




    $begingroup$
    Why not use Annulus?
    $endgroup$
    – Carl Woll
    1 hour ago
















2












$begingroup$


I want to put an anulus in my graphics object. How can I format a region difference into a graphics primitive?



a=1;b=5;
Region[RegionDifference[Disk[{0,0},b],Disk[{0,0},a]]] (*works*)
Graphics[{Rectangle[{5,5}], Blue,Rectangle[{-5,-5}],RegionDifference[Disk[{0,0},b],Disk[{0,0},a]]}](*doesn't work*)
Head[RegionDifference[Disk[{0,0},b],Disk[{0,0},a]]] (* wrong object type *)
Head[Disk[]]









share|improve this question









$endgroup$








  • 4




    $begingroup$
    Why not use Annulus?
    $endgroup$
    – Carl Woll
    1 hour ago














2












2








2





$begingroup$


I want to put an anulus in my graphics object. How can I format a region difference into a graphics primitive?



a=1;b=5;
Region[RegionDifference[Disk[{0,0},b],Disk[{0,0},a]]] (*works*)
Graphics[{Rectangle[{5,5}], Blue,Rectangle[{-5,-5}],RegionDifference[Disk[{0,0},b],Disk[{0,0},a]]}](*doesn't work*)
Head[RegionDifference[Disk[{0,0},b],Disk[{0,0},a]]] (* wrong object type *)
Head[Disk[]]









share|improve this question









$endgroup$




I want to put an anulus in my graphics object. How can I format a region difference into a graphics primitive?



a=1;b=5;
Region[RegionDifference[Disk[{0,0},b],Disk[{0,0},a]]] (*works*)
Graphics[{Rectangle[{5,5}], Blue,Rectangle[{-5,-5}],RegionDifference[Disk[{0,0},b],Disk[{0,0},a]]}](*doesn't work*)
Head[RegionDifference[Disk[{0,0},b],Disk[{0,0},a]]] (* wrong object type *)
Head[Disk[]]






graphics regions






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 2 hours ago









Ion SmeIon Sme

626




626








  • 4




    $begingroup$
    Why not use Annulus?
    $endgroup$
    – Carl Woll
    1 hour ago














  • 4




    $begingroup$
    Why not use Annulus?
    $endgroup$
    – Carl Woll
    1 hour ago








4




4




$begingroup$
Why not use Annulus?
$endgroup$
– Carl Woll
1 hour ago




$begingroup$
Why not use Annulus?
$endgroup$
– Carl Woll
1 hour ago










3 Answers
3






active

oldest

votes


















2












$begingroup$

Graphics[{Rectangle[{5, 5}], Blue, Rectangle[{-5, -5}], 
First @ RegionPlot @ RegionDifference[Disk[{0, 0}, b], Disk[{0, 0}, a]]}]


enter image description here






share|improve this answer









$endgroup$





















    2












    $begingroup$

    a = 1; b = 5;
    Show[Graphics[{Blue, Rectangle[{4, 4}], {Red, Rectangle[{-5, -5}]}}],
    Region[RegionDifference[Disk[{0, 0}, b], Disk[{0, 0}, a]]]]


    enter image description here






    share|improve this answer









    $endgroup$





















      1












      $begingroup$

      Graphics[Annulus[{0, 0}, {.5, 1}]]


      (* Oh... just saw @Carl Woll's equivalent solution *)






      share|improve this answer









      $endgroup$














        Your Answer





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        3 Answers
        3






        active

        oldest

        votes








        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        2












        $begingroup$

        Graphics[{Rectangle[{5, 5}], Blue, Rectangle[{-5, -5}], 
        First @ RegionPlot @ RegionDifference[Disk[{0, 0}, b], Disk[{0, 0}, a]]}]


        enter image description here






        share|improve this answer









        $endgroup$


















          2












          $begingroup$

          Graphics[{Rectangle[{5, 5}], Blue, Rectangle[{-5, -5}], 
          First @ RegionPlot @ RegionDifference[Disk[{0, 0}, b], Disk[{0, 0}, a]]}]


          enter image description here






          share|improve this answer









          $endgroup$
















            2












            2








            2





            $begingroup$

            Graphics[{Rectangle[{5, 5}], Blue, Rectangle[{-5, -5}], 
            First @ RegionPlot @ RegionDifference[Disk[{0, 0}, b], Disk[{0, 0}, a]]}]


            enter image description here






            share|improve this answer









            $endgroup$



            Graphics[{Rectangle[{5, 5}], Blue, Rectangle[{-5, -5}], 
            First @ RegionPlot @ RegionDifference[Disk[{0, 0}, b], Disk[{0, 0}, a]]}]


            enter image description here







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 1 hour ago









            kglrkglr

            190k10206424




            190k10206424























                2












                $begingroup$

                a = 1; b = 5;
                Show[Graphics[{Blue, Rectangle[{4, 4}], {Red, Rectangle[{-5, -5}]}}],
                Region[RegionDifference[Disk[{0, 0}, b], Disk[{0, 0}, a]]]]


                enter image description here






                share|improve this answer









                $endgroup$


















                  2












                  $begingroup$

                  a = 1; b = 5;
                  Show[Graphics[{Blue, Rectangle[{4, 4}], {Red, Rectangle[{-5, -5}]}}],
                  Region[RegionDifference[Disk[{0, 0}, b], Disk[{0, 0}, a]]]]


                  enter image description here






                  share|improve this answer









                  $endgroup$
















                    2












                    2








                    2





                    $begingroup$

                    a = 1; b = 5;
                    Show[Graphics[{Blue, Rectangle[{4, 4}], {Red, Rectangle[{-5, -5}]}}],
                    Region[RegionDifference[Disk[{0, 0}, b], Disk[{0, 0}, a]]]]


                    enter image description here






                    share|improve this answer









                    $endgroup$



                    a = 1; b = 5;
                    Show[Graphics[{Blue, Rectangle[{4, 4}], {Red, Rectangle[{-5, -5}]}}],
                    Region[RegionDifference[Disk[{0, 0}, b], Disk[{0, 0}, a]]]]


                    enter image description here







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered 1 hour ago









                    mjwmjw

                    1,09910




                    1,09910























                        1












                        $begingroup$

                        Graphics[Annulus[{0, 0}, {.5, 1}]]


                        (* Oh... just saw @Carl Woll's equivalent solution *)






                        share|improve this answer









                        $endgroup$


















                          1












                          $begingroup$

                          Graphics[Annulus[{0, 0}, {.5, 1}]]


                          (* Oh... just saw @Carl Woll's equivalent solution *)






                          share|improve this answer









                          $endgroup$
















                            1












                            1








                            1





                            $begingroup$

                            Graphics[Annulus[{0, 0}, {.5, 1}]]


                            (* Oh... just saw @Carl Woll's equivalent solution *)






                            share|improve this answer









                            $endgroup$



                            Graphics[Annulus[{0, 0}, {.5, 1}]]


                            (* Oh... just saw @Carl Woll's equivalent solution *)







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 1 hour ago









                            David G. StorkDavid G. Stork

                            24.8k22155




                            24.8k22155






























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