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Count number of li element and addclass

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Count number of li element and addclass



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6















I am trying to count LI elements, and addclass to another div.



For example,






$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>


<div class="box2">text</div>





This should be like this



<div class="box2 list3">text</div>


But I don't know why when I check on the DOM code,



<div class="box2 list0">text</div>


I get this result.



What do I need to fix the code?
Please help.










share|improve this question


















  • 1





    Your $(this) is not pointing to .box2 as you expect

    – Mr. Alien
    1 hour ago











  • @Mr.Alien It is what it actually does, pointing to .box2, hence not working as expected as there is no .box1 after it.

    – LGSon
    52 mins ago













  • @Mr.Alien A console.log($(this) shows that $(this) is pointing to .box2. If you reverse the HTML structure of box1 and box2 and change the JavaScript to return 'list' + $(this).find('+ .box1 li').length;, you'll see it's working properly using the adjacent sibling selector added to the start of find.

    – Andy Hoffman
    47 mins ago











  • It would be great to add $(document).ready(function(){, around your JQuery operations,

    – harish sharma
    14 mins ago
















6















I am trying to count LI elements, and addclass to another div.



For example,






$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>


<div class="box2">text</div>





This should be like this



<div class="box2 list3">text</div>


But I don't know why when I check on the DOM code,



<div class="box2 list0">text</div>


I get this result.



What do I need to fix the code?
Please help.










share|improve this question


















  • 1





    Your $(this) is not pointing to .box2 as you expect

    – Mr. Alien
    1 hour ago











  • @Mr.Alien It is what it actually does, pointing to .box2, hence not working as expected as there is no .box1 after it.

    – LGSon
    52 mins ago













  • @Mr.Alien A console.log($(this) shows that $(this) is pointing to .box2. If you reverse the HTML structure of box1 and box2 and change the JavaScript to return 'list' + $(this).find('+ .box1 li').length;, you'll see it's working properly using the adjacent sibling selector added to the start of find.

    – Andy Hoffman
    47 mins ago











  • It would be great to add $(document).ready(function(){, around your JQuery operations,

    – harish sharma
    14 mins ago














6












6








6








I am trying to count LI elements, and addclass to another div.



For example,






$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>


<div class="box2">text</div>





This should be like this



<div class="box2 list3">text</div>


But I don't know why when I check on the DOM code,



<div class="box2 list0">text</div>


I get this result.



What do I need to fix the code?
Please help.










share|improve this question














I am trying to count LI elements, and addclass to another div.



For example,






$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>


<div class="box2">text</div>





This should be like this



<div class="box2 list3">text</div>


But I don't know why when I check on the DOM code,



<div class="box2 list0">text</div>


I get this result.



What do I need to fix the code?
Please help.






$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>


<div class="box2">text</div>





$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>


<div class="box2">text</div>






javascript html css






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 1 hour ago









kk kkkk kk

926




926








  • 1





    Your $(this) is not pointing to .box2 as you expect

    – Mr. Alien
    1 hour ago











  • @Mr.Alien It is what it actually does, pointing to .box2, hence not working as expected as there is no .box1 after it.

    – LGSon
    52 mins ago













  • @Mr.Alien A console.log($(this) shows that $(this) is pointing to .box2. If you reverse the HTML structure of box1 and box2 and change the JavaScript to return 'list' + $(this).find('+ .box1 li').length;, you'll see it's working properly using the adjacent sibling selector added to the start of find.

    – Andy Hoffman
    47 mins ago











  • It would be great to add $(document).ready(function(){, around your JQuery operations,

    – harish sharma
    14 mins ago














  • 1





    Your $(this) is not pointing to .box2 as you expect

    – Mr. Alien
    1 hour ago











  • @Mr.Alien It is what it actually does, pointing to .box2, hence not working as expected as there is no .box1 after it.

    – LGSon
    52 mins ago













  • @Mr.Alien A console.log($(this) shows that $(this) is pointing to .box2. If you reverse the HTML structure of box1 and box2 and change the JavaScript to return 'list' + $(this).find('+ .box1 li').length;, you'll see it's working properly using the adjacent sibling selector added to the start of find.

    – Andy Hoffman
    47 mins ago











  • It would be great to add $(document).ready(function(){, around your JQuery operations,

    – harish sharma
    14 mins ago








1




1





Your $(this) is not pointing to .box2 as you expect

– Mr. Alien
1 hour ago





Your $(this) is not pointing to .box2 as you expect

– Mr. Alien
1 hour ago













@Mr.Alien It is what it actually does, pointing to .box2, hence not working as expected as there is no .box1 after it.

– LGSon
52 mins ago







@Mr.Alien It is what it actually does, pointing to .box2, hence not working as expected as there is no .box1 after it.

– LGSon
52 mins ago















@Mr.Alien A console.log($(this) shows that $(this) is pointing to .box2. If you reverse the HTML structure of box1 and box2 and change the JavaScript to return 'list' + $(this).find('+ .box1 li').length;, you'll see it's working properly using the adjacent sibling selector added to the start of find.

– Andy Hoffman
47 mins ago





@Mr.Alien A console.log($(this) shows that $(this) is pointing to .box2. If you reverse the HTML structure of box1 and box2 and change the JavaScript to return 'list' + $(this).find('+ .box1 li').length;, you'll see it's working properly using the adjacent sibling selector added to the start of find.

– Andy Hoffman
47 mins ago













It would be great to add $(document).ready(function(){, around your JQuery operations,

– harish sharma
14 mins ago





It would be great to add $(document).ready(function(){, around your JQuery operations,

– harish sharma
14 mins ago












5 Answers
5






active

oldest

votes


















5














Pretty close. box1 comes before box2, so your query beginning at box2, or $(this), would return 0 results as find looks ahead in the DOM.






$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>

<div class="box2">text</div>








share|improve this answer


























  • thank you for your answer :)

    – kk kk
    1 hour ago



















5














Here $(this) is referring to box2 element.Only $('.box1 li').length is what you required






$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});

.list_3 {
color: green;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>








share|improve this answer


























  • thank you this works perfectly

    – kk kk
    1 hour ago



















4














this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass() is invoked and this element does not have .box1 li. Thus find() is failing to refer your intended element.



Simply use:



$('.box1 li').length 





$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>








share|improve this answer

































    4














    $(this).find will find the li in the div with box2 class which are not present. Instead check this in the div with box1 class and find the li elements






    $('.box2').addClass(function(){
    return 'list' + $('.box1').find('li').length;
    });

    <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
    <ul class="box1">
    <li>a</li>
    <li>b</li>
    <li>c</li>
    </ul>


    <div class="box2">text</div>








    share|improve this answer

































      2














      You can simply do this by following method






      $('.box2').addClass('list' + $('.box1 li').length);

      <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
      <ul class="box1">
      <li>a</li>
      <li>b</li>
      <li>c</li>
      </ul>
      <div class="box2">text</div>








      share|improve this answer























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        5 Answers
        5






        active

        oldest

        votes








        5 Answers
        5






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        5














        Pretty close. box1 comes before box2, so your query beginning at box2, or $(this), would return 0 results as find looks ahead in the DOM.






        $('.box2').addClass(function(){
        return 'list' + $('.box1 li').length;
        });

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>

        <div class="box2">text</div>








        share|improve this answer


























        • thank you for your answer :)

          – kk kk
          1 hour ago
















        5














        Pretty close. box1 comes before box2, so your query beginning at box2, or $(this), would return 0 results as find looks ahead in the DOM.






        $('.box2').addClass(function(){
        return 'list' + $('.box1 li').length;
        });

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>

        <div class="box2">text</div>








        share|improve this answer


























        • thank you for your answer :)

          – kk kk
          1 hour ago














        5












        5








        5







        Pretty close. box1 comes before box2, so your query beginning at box2, or $(this), would return 0 results as find looks ahead in the DOM.






        $('.box2').addClass(function(){
        return 'list' + $('.box1 li').length;
        });

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>

        <div class="box2">text</div>








        share|improve this answer















        Pretty close. box1 comes before box2, so your query beginning at box2, or $(this), would return 0 results as find looks ahead in the DOM.






        $('.box2').addClass(function(){
        return 'list' + $('.box1 li').length;
        });

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>

        <div class="box2">text</div>








        $('.box2').addClass(function(){
        return 'list' + $('.box1 li').length;
        });

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>

        <div class="box2">text</div>





        $('.box2').addClass(function(){
        return 'list' + $('.box1 li').length;
        });

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>

        <div class="box2">text</div>






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 1 hour ago

























        answered 1 hour ago









        Andy HoffmanAndy Hoffman

        8,07631538




        8,07631538













        • thank you for your answer :)

          – kk kk
          1 hour ago



















        • thank you for your answer :)

          – kk kk
          1 hour ago

















        thank you for your answer :)

        – kk kk
        1 hour ago





        thank you for your answer :)

        – kk kk
        1 hour ago













        5














        Here $(this) is referring to box2 element.Only $('.box1 li').length is what you required






        $('.box2').addClass(function() {
        return 'list_' + $('.box1 li').length;
        });

        .list_3 {
        color: green;
        }

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>
        <div class="box2">text</div>








        share|improve this answer


























        • thank you this works perfectly

          – kk kk
          1 hour ago
















        5














        Here $(this) is referring to box2 element.Only $('.box1 li').length is what you required






        $('.box2').addClass(function() {
        return 'list_' + $('.box1 li').length;
        });

        .list_3 {
        color: green;
        }

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>
        <div class="box2">text</div>








        share|improve this answer


























        • thank you this works perfectly

          – kk kk
          1 hour ago














        5












        5








        5







        Here $(this) is referring to box2 element.Only $('.box1 li').length is what you required






        $('.box2').addClass(function() {
        return 'list_' + $('.box1 li').length;
        });

        .list_3 {
        color: green;
        }

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>
        <div class="box2">text</div>








        share|improve this answer















        Here $(this) is referring to box2 element.Only $('.box1 li').length is what you required






        $('.box2').addClass(function() {
        return 'list_' + $('.box1 li').length;
        });

        .list_3 {
        color: green;
        }

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>
        <div class="box2">text</div>








        $('.box2').addClass(function() {
        return 'list_' + $('.box1 li').length;
        });

        .list_3 {
        color: green;
        }

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>
        <div class="box2">text</div>





        $('.box2').addClass(function() {
        return 'list_' + $('.box1 li').length;
        });

        .list_3 {
        color: green;
        }

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>
        <div class="box2">text</div>






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 1 hour ago

























        answered 1 hour ago









        brkbrk

        28.4k32143




        28.4k32143













        • thank you this works perfectly

          – kk kk
          1 hour ago



















        • thank you this works perfectly

          – kk kk
          1 hour ago

















        thank you this works perfectly

        – kk kk
        1 hour ago





        thank you this works perfectly

        – kk kk
        1 hour ago











        4














        this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass() is invoked and this element does not have .box1 li. Thus find() is failing to refer your intended element.



        Simply use:



        $('.box1 li').length 





        $('.box2').addClass(function(){
        console.log(this.nodeName); // DIV
        return 'list' + $('.box1 li').length;
        });

        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <ul class="box1">
        <li>a</li>
        <li>b</li>
        <li>c</li>
        </ul>
        <div class="box2">text</div>








        share|improve this answer






























          4














          this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass() is invoked and this element does not have .box1 li. Thus find() is failing to refer your intended element.



          Simply use:



          $('.box1 li').length 





          $('.box2').addClass(function(){
          console.log(this.nodeName); // DIV
          return 'list' + $('.box1 li').length;
          });

          <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
          <ul class="box1">
          <li>a</li>
          <li>b</li>
          <li>c</li>
          </ul>
          <div class="box2">text</div>








          share|improve this answer




























            4












            4








            4







            this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass() is invoked and this element does not have .box1 li. Thus find() is failing to refer your intended element.



            Simply use:



            $('.box1 li').length 





            $('.box2').addClass(function(){
            console.log(this.nodeName); // DIV
            return 'list' + $('.box1 li').length;
            });

            <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
            <ul class="box1">
            <li>a</li>
            <li>b</li>
            <li>c</li>
            </ul>
            <div class="box2">text</div>








            share|improve this answer















            this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass() is invoked and this element does not have .box1 li. Thus find() is failing to refer your intended element.



            Simply use:



            $('.box1 li').length 





            $('.box2').addClass(function(){
            console.log(this.nodeName); // DIV
            return 'list' + $('.box1 li').length;
            });

            <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
            <ul class="box1">
            <li>a</li>
            <li>b</li>
            <li>c</li>
            </ul>
            <div class="box2">text</div>








            $('.box2').addClass(function(){
            console.log(this.nodeName); // DIV
            return 'list' + $('.box1 li').length;
            });

            <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
            <ul class="box1">
            <li>a</li>
            <li>b</li>
            <li>c</li>
            </ul>
            <div class="box2">text</div>





            $('.box2').addClass(function(){
            console.log(this.nodeName); // DIV
            return 'list' + $('.box1 li').length;
            });

            <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
            <ul class="box1">
            <li>a</li>
            <li>b</li>
            <li>c</li>
            </ul>
            <div class="box2">text</div>






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 58 mins ago

























            answered 1 hour ago









            MamunMamun

            29k71831




            29k71831























                4














                $(this).find will find the li in the div with box2 class which are not present. Instead check this in the div with box1 class and find the li elements






                $('.box2').addClass(function(){
                return 'list' + $('.box1').find('li').length;
                });

                <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
                <ul class="box1">
                <li>a</li>
                <li>b</li>
                <li>c</li>
                </ul>


                <div class="box2">text</div>








                share|improve this answer






























                  4














                  $(this).find will find the li in the div with box2 class which are not present. Instead check this in the div with box1 class and find the li elements






                  $('.box2').addClass(function(){
                  return 'list' + $('.box1').find('li').length;
                  });

                  <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
                  <ul class="box1">
                  <li>a</li>
                  <li>b</li>
                  <li>c</li>
                  </ul>


                  <div class="box2">text</div>








                  share|improve this answer




























                    4












                    4








                    4







                    $(this).find will find the li in the div with box2 class which are not present. Instead check this in the div with box1 class and find the li elements






                    $('.box2').addClass(function(){
                    return 'list' + $('.box1').find('li').length;
                    });

                    <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
                    <ul class="box1">
                    <li>a</li>
                    <li>b</li>
                    <li>c</li>
                    </ul>


                    <div class="box2">text</div>








                    share|improve this answer















                    $(this).find will find the li in the div with box2 class which are not present. Instead check this in the div with box1 class and find the li elements






                    $('.box2').addClass(function(){
                    return 'list' + $('.box1').find('li').length;
                    });

                    <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
                    <ul class="box1">
                    <li>a</li>
                    <li>b</li>
                    <li>c</li>
                    </ul>


                    <div class="box2">text</div>








                    $('.box2').addClass(function(){
                    return 'list' + $('.box1').find('li').length;
                    });

                    <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
                    <ul class="box1">
                    <li>a</li>
                    <li>b</li>
                    <li>c</li>
                    </ul>


                    <div class="box2">text</div>





                    $('.box2').addClass(function(){
                    return 'list' + $('.box1').find('li').length;
                    });

                    <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
                    <ul class="box1">
                    <li>a</li>
                    <li>b</li>
                    <li>c</li>
                    </ul>


                    <div class="box2">text</div>






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 25 mins ago

























                    answered 1 hour ago









                    ellipsisellipsis

                    7,6982929




                    7,6982929























                        2














                        You can simply do this by following method






                        $('.box2').addClass('list' + $('.box1 li').length);

                        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
                        <ul class="box1">
                        <li>a</li>
                        <li>b</li>
                        <li>c</li>
                        </ul>
                        <div class="box2">text</div>








                        share|improve this answer




























                          2














                          You can simply do this by following method






                          $('.box2').addClass('list' + $('.box1 li').length);

                          <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
                          <ul class="box1">
                          <li>a</li>
                          <li>b</li>
                          <li>c</li>
                          </ul>
                          <div class="box2">text</div>








                          share|improve this answer


























                            2












                            2








                            2







                            You can simply do this by following method






                            $('.box2').addClass('list' + $('.box1 li').length);

                            <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
                            <ul class="box1">
                            <li>a</li>
                            <li>b</li>
                            <li>c</li>
                            </ul>
                            <div class="box2">text</div>








                            share|improve this answer













                            You can simply do this by following method






                            $('.box2').addClass('list' + $('.box1 li').length);

                            <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
                            <ul class="box1">
                            <li>a</li>
                            <li>b</li>
                            <li>c</li>
                            </ul>
                            <div class="box2">text</div>








                            $('.box2').addClass('list' + $('.box1 li').length);

                            <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
                            <ul class="box1">
                            <li>a</li>
                            <li>b</li>
                            <li>c</li>
                            </ul>
                            <div class="box2">text</div>





                            $('.box2').addClass('list' + $('.box1 li').length);

                            <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
                            <ul class="box1">
                            <li>a</li>
                            <li>b</li>
                            <li>c</li>
                            </ul>
                            <div class="box2">text</div>






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 1 hour ago









                            Sarabjit SinghSarabjit Singh

                            1169




                            1169






























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