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Coordinates unit in pt although default is cm in TikZ
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As we know that in TikZ, if unit is not mentioned in the coordinate in TikZ, it takes cm
by default.
When I extract the coordinates, I was expecting the unit as cm
. But TikZ shows the unit in the coordinate as pt
.
How does TikZ determine the unit of measure in a coordinate if no unit is specified.
MWE:
documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}
newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}
begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);
draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);
node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {(XCoord,YCoord)};
end{tikzpicture}
end{document}
tikz-pgf unit-of-measure
|
show 7 more comments
As we know that in TikZ, if unit is not mentioned in the coordinate in TikZ, it takes cm
by default.
When I extract the coordinates, I was expecting the unit as cm
. But TikZ shows the unit in the coordinate as pt
.
How does TikZ determine the unit of measure in a coordinate if no unit is specified.
MWE:
documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}
newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}
begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);
draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);
node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {(XCoord,YCoord)};
end{tikzpicture}
end{document}
tikz-pgf unit-of-measure
Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579
– barbara beeton
4 hours ago
Barbara I would like to know the default unit of measure when unit of measure is not mentioned
– subham soni
4 hours ago
1
Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .
– marmot
4 hours ago
How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?
– zyy
4 hours ago
@zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)
– marmot
4 hours ago
|
show 7 more comments
As we know that in TikZ, if unit is not mentioned in the coordinate in TikZ, it takes cm
by default.
When I extract the coordinates, I was expecting the unit as cm
. But TikZ shows the unit in the coordinate as pt
.
How does TikZ determine the unit of measure in a coordinate if no unit is specified.
MWE:
documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}
newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}
begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);
draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);
node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {(XCoord,YCoord)};
end{tikzpicture}
end{document}
tikz-pgf unit-of-measure
As we know that in TikZ, if unit is not mentioned in the coordinate in TikZ, it takes cm
by default.
When I extract the coordinates, I was expecting the unit as cm
. But TikZ shows the unit in the coordinate as pt
.
How does TikZ determine the unit of measure in a coordinate if no unit is specified.
MWE:
documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}
newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}
begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);
draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);
node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {(XCoord,YCoord)};
end{tikzpicture}
end{document}
tikz-pgf unit-of-measure
tikz-pgf unit-of-measure
asked 5 hours ago
subham sonisubham soni
4,00582981
4,00582981
Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579
– barbara beeton
4 hours ago
Barbara I would like to know the default unit of measure when unit of measure is not mentioned
– subham soni
4 hours ago
1
Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .
– marmot
4 hours ago
How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?
– zyy
4 hours ago
@zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)
– marmot
4 hours ago
|
show 7 more comments
Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579
– barbara beeton
4 hours ago
Barbara I would like to know the default unit of measure when unit of measure is not mentioned
– subham soni
4 hours ago
1
Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .
– marmot
4 hours ago
How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?
– zyy
4 hours ago
@zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)
– marmot
4 hours ago
Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579
– barbara beeton
4 hours ago
Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579
– barbara beeton
4 hours ago
Barbara I would like to know the default unit of measure when unit of measure is not mentioned
– subham soni
4 hours ago
Barbara I would like to know the default unit of measure when unit of measure is not mentioned
– subham soni
4 hours ago
1
1
Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .
– marmot
4 hours ago
Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .
– marmot
4 hours ago
How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?
– zyy
4 hours ago
How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?
– zyy
4 hours ago
@zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)
– marmot
4 hours ago
@zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)
– marmot
4 hours ago
|
show 7 more comments
1 Answer
1
active
oldest
votes
You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm
or its inverse. (If that's not what you're after, I will be happy to remove the post.)
documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}
newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}
begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);
draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);
node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {%
(pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%
pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};
end{tikzpicture}
end{document}
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm
or its inverse. (If that's not what you're after, I will be happy to remove the post.)
documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}
newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}
begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);
draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);
node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {%
(pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%
pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};
end{tikzpicture}
end{document}
add a comment |
You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm
or its inverse. (If that's not what you're after, I will be happy to remove the post.)
documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}
newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}
begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);
draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);
node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {%
(pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%
pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};
end{tikzpicture}
end{document}
add a comment |
You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm
or its inverse. (If that's not what you're after, I will be happy to remove the post.)
documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}
newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}
begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);
draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);
node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {%
(pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%
pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};
end{tikzpicture}
end{document}
You can always convert everything from pt to cm or back by multiplying by the ratio 1pt/1cm
or its inverse. (If that's not what you're after, I will be happy to remove the post.)
documentclass{article}
usepackage{tikz}
usetikzlibrary{decorations.pathmorphing}
usetikzlibrary{decorations.markings}
usetikzlibrary{calc}
usetikzlibrary{positioning}
tikzset{zigzag/.style={decorate,decoration=zigzag}}
begin{document}
newdimenXCoord
newdimenYCoord
newcommand*{ExtractCoordinate}[1]{path (#1); pgfgetlastxy{XCoord}{YCoord};}
begin{tikzpicture}
coordinate (c) at (0,-2);
coordinate (d) at (4,-2);
coordinate (e) at (2,-4);
draw[thick,red,zigzag,postaction={
decoration={
markings,
mark=at position 0.7 with { coordinate (x); },
mark=at position 0.5 with { coordinate (singularity); },
},
decorate
}] (-2,0) coordinate(a) -- (2,0) coordinate(b);
draw[thick,fill=blue!20] (c) -- (b) -- (d) -- (e) -- cycle;
draw[thick,postaction={
decoration={
markings,
mark = at position 0.7 with coordinate (y);
},
decorate
}] (a) -- (c);
draw[thick,red,dashed] (x) -- (y);
node[above = 10ex of singularity,red] (sn) {singularity};
draw[red,->] (sn) -- ($(singularity)+(0,1)$);
ExtractCoordinate{x};
node[above] at (XCoord,YCoord) {%
(pgfmathparse{XCoord*1pt/1cm}pgfmathprintnumber{pgfmathresult},cm,%
pgfmathparse{YCoord*1pt/1cm}pgfmathprintnumber[fixed,precision=2]{pgfmathresult},cm)};
end{tikzpicture}
end{document}
answered 4 hours ago
marmotmarmot
104k4123236
104k4123236
add a comment |
add a comment |
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Not an answer, but the information may be useful: tex.stackexchange.com/a/20069/579
– barbara beeton
4 hours ago
Barbara I would like to know the default unit of measure when unit of measure is not mentioned
– subham soni
4 hours ago
1
Internally TikZ works with pt. You have a coordinate system in which the unit vectors have length 1cm. Does that make sense? The IMHO clearest discussion on this can be found at tex.stackexchange.com/a/31606/121799 .
– marmot
4 hours ago
How did you measure the distance though? How did you make sure you are not magnifying the document when measuring?
– zyy
4 hours ago
@zyy As far as I can see, there is only the word singularity, not a real singularity, so you can use the Euclidean metric to a good approximation. ;-)
– marmot
4 hours ago