Sfdwhf

Is there a name for this algorithm to calculate the concentration of a mixture of two solutions containing the same solute?

What does routing an IP address mean?

Non-trope happy ending?

Start making guitar arrangements

How much character growth crosses the line into breaking the character

Not using 's' for he/she/it

Creepy dinosaur pc game identification

Strong empirical falsification of quantum mechanics based on vacuum energy density

What are the purposes of autoencoders?

Multiplicative persistence

When were female captains banned from Starfleet?

why `nmap 192.168.1.97` returns less services than `nmap 127.0.0.1`?

Is this toilet slogan correct usage of the English language?

Why did the EU agree to delay the Brexit deadline?

Aragorn's "guise" in the Orthanc Stone

copy and scale one figure (wheel)

Store Credit Card Information in Password Manager?

What should you do if you miss a job interview (deliberately)?

Count the occurrence of each unique word in the file

How can Trident be so inexpensive? Will it orbit Triton or just do a (slow) flyby?

What if a revenant (monster) gains fire resistance?

Existing of non-intersecting rays

Is it improper etiquette to ask your opponent what his/her rating is before the game?

Is it possible to have a strip of cold climate in the middle of a planet?

Create all possible words using a set or letters

Finding all length-n words on an alphabet that have a specified number of each letterFinding all dictionary words that can be made with a given set of characters (Wordfeud/Scrabble)How to enumerate all possible binary associations?Sorting an Array with words in different languagesUsing StringCases and treating certain phrases as single wordsGraph showing valid English words obtained by insertion of single charactersTrim a list of elementsList all possible microstates and corresponding energy using mathematica.Selecting words having a specific number of letters from a textSelecting elements using two lists

1

$begingroup$

Given a list of letters,

letters = { "A", "B", ..., "F" }

is it possible to get Mathematica to generate all ‘words’ (in this example, 6 letter words), if only one letter can be used one time only, e.g. ABCDEF, ABCDFE, …? TIA.

string-manipulation combinatorics

share|improve this question

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

asked 1 hour ago

mf67mf67

975

$endgroup$

add a comment | 

1

$begingroup$

Given a list of letters,

letters = { "A", "B", ..., "F" }

is it possible to get Mathematica to generate all ‘words’ (in this example, 6 letter words), if only one letter can be used one time only, e.g. ABCDEF, ABCDFE, …? TIA.

string-manipulation combinatorics

share|improve this question

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

asked 1 hour ago

mf67mf67

975

$endgroup$

add a comment | 

$begingroup$

Given a list of letters,

letters = { "A", "B", ..., "F" }

is it possible to get Mathematica to generate all ‘words’ (in this example, 6 letter words), if only one letter can be used one time only, e.g. ABCDEF, ABCDFE, …? TIA.

string-manipulation combinatorics

share|improve this question

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

asked 1 hour ago

mf67mf67

975

$endgroup$

letters = { "A", "B", ..., "F" }

share|improve this question

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

asked 1 hour ago

mf67mf67

975

share|improve this question

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

asked 1 hour ago

mf67mf67

975

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

asked 1 hour ago

mf67mf67

975

asked 1 hour ago

mf67mf67

975

2 Answers
2

active

oldest

votes

2

$begingroup$

You can create permutations with all of the letters as strings with:

StringJoin /@ Permutations[letters]

If you want lists of the individual letters just use:

Permutations[letters]

Check the documentation of Permutations to learn about permutations with subsets of letters. If you want to use each letter more than once, look at the documentation for Tuples.

share|improve this answer

answered 1 hour ago

LeeLee

45027

$endgroup$

add a comment | 

1

$begingroup$

Pemutations will do it:

letters = {"a", "b", "c"};

Permutations[letters, {3}]

{{"a", "b", "c"}, {"a", "c", "b"}, {"b", "a", "c"}, 

 {"b", "c", "a"}, {"c", "a", "b"}, {"c", "b", "a"}}

share|improve this answer

answered 1 hour ago

bill sbill s

54.6k377156

$endgroup$

add a comment | 

Your Answer

StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f193857%2fcreate-all-possible-words-using-a-set-or-letters%23new-answer', 'question_page');
}
);

Post as a guest

Name

Email

Required, but never shown

2

$begingroup$

You can create permutations with all of the letters as strings with:

StringJoin /@ Permutations[letters]

If you want lists of the individual letters just use:

Permutations[letters]

Check the documentation of Permutations to learn about permutations with subsets of letters. If you want to use each letter more than once, look at the documentation for Tuples.

share|improve this answer

answered 1 hour ago

LeeLee

45027

$endgroup$

add a comment | 

2

$begingroup$

You can create permutations with all of the letters as strings with:

StringJoin /@ Permutations[letters]

If you want lists of the individual letters just use:

Permutations[letters]

Check the documentation of Permutations to learn about permutations with subsets of letters. If you want to use each letter more than once, look at the documentation for Tuples.

share|improve this answer

answered 1 hour ago

LeeLee

45027

$endgroup$

add a comment | 

$begingroup$

You can create permutations with all of the letters as strings with:

StringJoin /@ Permutations[letters]

If you want lists of the individual letters just use:

Permutations[letters]

Check the documentation of Permutations to learn about permutations with subsets of letters. If you want to use each letter more than once, look at the documentation for Tuples.

share|improve this answer

answered 1 hour ago

LeeLee

45027

$endgroup$

StringJoin /@ Permutations[letters]

Permutations[letters]

share|improve this answer

answered 1 hour ago

LeeLee

45027

answered 1 hour ago

LeeLee

45027

answered 1 hour ago

LeeLee

45027

1

$begingroup$

Pemutations will do it:

letters = {"a", "b", "c"};

Permutations[letters, {3}]

{{"a", "b", "c"}, {"a", "c", "b"}, {"b", "a", "c"}, 

 {"b", "c", "a"}, {"c", "a", "b"}, {"c", "b", "a"}}

share|improve this answer

answered 1 hour ago

bill sbill s

54.6k377156

$endgroup$

add a comment | 

1

$begingroup$

Pemutations will do it:

letters = {"a", "b", "c"};

Permutations[letters, {3}]

{{"a", "b", "c"}, {"a", "c", "b"}, {"b", "a", "c"}, 

 {"b", "c", "a"}, {"c", "a", "b"}, {"c", "b", "a"}}

share|improve this answer

answered 1 hour ago

bill sbill s

54.6k377156

$endgroup$

add a comment | 

$begingroup$

Pemutations will do it:

letters = {"a", "b", "c"};

Permutations[letters, {3}]

{{"a", "b", "c"}, {"a", "c", "b"}, {"b", "a", "c"}, 

 {"b", "c", "a"}, {"c", "a", "b"}, {"c", "b", "a"}}

share|improve this answer

answered 1 hour ago

bill sbill s

54.6k377156

$endgroup$

letters = {"a", "b", "c"};

Permutations[letters, {3}]

{{"a", "b", "c"}, {"a", "c", "b"}, {"b", "a", "c"}, 

 {"b", "c", "a"}, {"c", "a", "b"}, {"c", "b", "a"}}

share|improve this answer

answered 1 hour ago

bill sbill s

54.6k377156

answered 1 hour ago

bill sbill s

54.6k377156

answered 1 hour ago

bill sbill s

54.6k377156