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Existing of non-intersecting rays


Constructing a circle through a point in the interior of an angleHow many rays can made from $4$ collinear points?Angle between different rays (3d line segments) and computing their angular relationshipsIntersecting three rays and a sphere of known radiusDesigning a distance function between raysLines between point and sphere surface intersecting a planeIntersecting planes stereometry problemIs a single line, line segment, or ray a valid angle?Coxeter, Introduction to Geometry, ordered geometry, parallelism of rays and linesNon-congruent angle of an isosceles triangle













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$begingroup$


Given $n$ points on a plane, it seems intuitive that it’s possible to draw a ray (half-line) from each point s. t. the $n$ rays do not intersect.



But how to prove this?










share|cite|improve this question









$endgroup$

















    2












    $begingroup$


    Given $n$ points on a plane, it seems intuitive that it’s possible to draw a ray (half-line) from each point s. t. the $n$ rays do not intersect.



    But how to prove this?










    share|cite|improve this question









    $endgroup$















      2












      2








      2


      1



      $begingroup$


      Given $n$ points on a plane, it seems intuitive that it’s possible to draw a ray (half-line) from each point s. t. the $n$ rays do not intersect.



      But how to prove this?










      share|cite|improve this question









      $endgroup$




      Given $n$ points on a plane, it seems intuitive that it’s possible to draw a ray (half-line) from each point s. t. the $n$ rays do not intersect.



      But how to prove this?







      geometry






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked 26 mins ago









      athosathos

      98611340




      98611340






















          1 Answer
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          active

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          2












          $begingroup$

          Pick any point $P$ in the plane that is not on a line containing two or more of the given $n$ points. At each point, draw the ray in the direction away from $P$.



          One can in fact do better: It is possible to draw lines through all $n$ points that do not intersect. Choose an orientation that is not parallel to any of the lines between any two of the given points, and draw parallel lines in that orientation through each point.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            +1 for being slightly faster than me :)
            $endgroup$
            – Severin Schraven
            14 mins ago










          • $begingroup$
            Thx ! This is a “oh of course “ moment of me
            $endgroup$
            – athos
            13 mins ago











          Your Answer





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          1 Answer
          1






          active

          oldest

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          active

          oldest

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          active

          oldest

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          2












          $begingroup$

          Pick any point $P$ in the plane that is not on a line containing two or more of the given $n$ points. At each point, draw the ray in the direction away from $P$.



          One can in fact do better: It is possible to draw lines through all $n$ points that do not intersect. Choose an orientation that is not parallel to any of the lines between any two of the given points, and draw parallel lines in that orientation through each point.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            +1 for being slightly faster than me :)
            $endgroup$
            – Severin Schraven
            14 mins ago










          • $begingroup$
            Thx ! This is a “oh of course “ moment of me
            $endgroup$
            – athos
            13 mins ago
















          2












          $begingroup$

          Pick any point $P$ in the plane that is not on a line containing two or more of the given $n$ points. At each point, draw the ray in the direction away from $P$.



          One can in fact do better: It is possible to draw lines through all $n$ points that do not intersect. Choose an orientation that is not parallel to any of the lines between any two of the given points, and draw parallel lines in that orientation through each point.






          share|cite|improve this answer











          $endgroup$













          • $begingroup$
            +1 for being slightly faster than me :)
            $endgroup$
            – Severin Schraven
            14 mins ago










          • $begingroup$
            Thx ! This is a “oh of course “ moment of me
            $endgroup$
            – athos
            13 mins ago














          2












          2








          2





          $begingroup$

          Pick any point $P$ in the plane that is not on a line containing two or more of the given $n$ points. At each point, draw the ray in the direction away from $P$.



          One can in fact do better: It is possible to draw lines through all $n$ points that do not intersect. Choose an orientation that is not parallel to any of the lines between any two of the given points, and draw parallel lines in that orientation through each point.






          share|cite|improve this answer











          $endgroup$



          Pick any point $P$ in the plane that is not on a line containing two or more of the given $n$ points. At each point, draw the ray in the direction away from $P$.



          One can in fact do better: It is possible to draw lines through all $n$ points that do not intersect. Choose an orientation that is not parallel to any of the lines between any two of the given points, and draw parallel lines in that orientation through each point.







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited 8 mins ago

























          answered 14 mins ago









          FredHFredH

          2,6041021




          2,6041021












          • $begingroup$
            +1 for being slightly faster than me :)
            $endgroup$
            – Severin Schraven
            14 mins ago










          • $begingroup$
            Thx ! This is a “oh of course “ moment of me
            $endgroup$
            – athos
            13 mins ago


















          • $begingroup$
            +1 for being slightly faster than me :)
            $endgroup$
            – Severin Schraven
            14 mins ago










          • $begingroup$
            Thx ! This is a “oh of course “ moment of me
            $endgroup$
            – athos
            13 mins ago
















          $begingroup$
          +1 for being slightly faster than me :)
          $endgroup$
          – Severin Schraven
          14 mins ago




          $begingroup$
          +1 for being slightly faster than me :)
          $endgroup$
          – Severin Schraven
          14 mins ago












          $begingroup$
          Thx ! This is a “oh of course “ moment of me
          $endgroup$
          – athos
          13 mins ago




          $begingroup$
          Thx ! This is a “oh of course “ moment of me
          $endgroup$
          – athos
          13 mins ago


















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