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$begingroup$
Background:
The current Perfect Numbers challenge is rather flawed and complicated, since it asks you to output in a complex format involving the factors of the number. This is a purely decision-problem repost of the challenge.
Challenge
Given a positive integer through any standard input format, output whether it is not perfect.
A perfect number is a number that is equal to the sum of all its proper divisors (its positive divisors less than itself). For example, $6$ is a perfect number, since its divisors are $1,2,3$, which sum up to $6$, while $12$ is not a perfect number since its divisors ( $1,2,3,4,6$ ) sum up to $16$, not $12$.
Test Cases:
Imperfect:
1,12,13,18,20,1000,33550335
Perfect:
6,28,496,8128,33550336,8589869056
Rules
- Your program doesn't have to complete the larger test cases, if there's memory or time constraints, but it should be theoretically able to if it were given more memory/time.
- Output can be two distinct and consistent values through any allowed output format. If it isn't immediately obvious what represents Truthy/Falsey, please make sure to specify in your answer.
- This means your values don't have to be literally Truthy/Falsey. Your Truthy output may evaluate to false in your language and vice-versa.
code-golf number decision-problem number-theory factoring
asked 1 hour ago
Jo KingJo King
24.6k357126
$endgroup$
add a comment |
$begingroup$
Background:
The current Perfect Numbers challenge is rather flawed and complicated, since it asks you to output in a complex format involving the factors of the number. This is a purely decision-problem repost of the challenge.
Challenge
Given a positive integer through any standard input format, output whether it is not perfect.
A perfect number is a number that is equal to the sum of all its proper divisors (its positive divisors less than itself). For example, $6$ is a perfect number, since its divisors are $1,2,3$, which sum up to $6$, while $12$ is not a perfect number since its divisors ( $1,2,3,4,6$ ) sum up to $16$, not $12$.
Test Cases:
Imperfect:
1,12,13,18,20,1000,33550335
Perfect:
6,28,496,8128,33550336,8589869056
Rules
- Your program doesn't have to complete the larger test cases, if there's memory or time constraints, but it should be theoretically able to if it were given more memory/time.
- Output can be two distinct and consistent values through any allowed output format. If it isn't immediately obvious what represents Truthy/Falsey, please make sure to specify in your answer.
- This means your values don't have to be literally Truthy/Falsey. Your Truthy output may evaluate to false in your language and vice-versa.
code-golf number decision-problem number-theory factoring
asked 1 hour ago
Jo KingJo King
24.6k357126
$endgroup$
$begingroup$
Wait, so truthy is for values that aren't perfect, and falsey is for values that are?
$endgroup$
– Esolanging Fruit
50 mins ago
$begingroup$
@EsolangingFruit Yes, though the actual output values don't really matter, so you can output true for perfect numbers if you wish
$endgroup$
– Jo King
48 mins ago
$begingroup$
Fair enough, but wording the challenge as "output whether it is not perfect" makes the test cases slightly confusing if you interpret "truthy" as meaning "values corresponding to true".
$endgroup$
– Esolanging Fruit
47 mins ago
$begingroup$
@EsolangingFruit Good point. I've renamed the test cases toImperfect/Perfectto make it clearer
$endgroup$
– Jo King
45 mins ago
add a comment |
$begingroup$
Background:
The current Perfect Numbers challenge is rather flawed and complicated, since it asks you to output in a complex format involving the factors of the number. This is a purely decision-problem repost of the challenge.
Challenge
Given a positive integer through any standard input format, output whether it is not perfect.
A perfect number is a number that is equal to the sum of all its proper divisors (its positive divisors less than itself). For example, $6$ is a perfect number, since its divisors are $1,2,3$, which sum up to $6$, while $12$ is not a perfect number since its divisors ( $1,2,3,4,6$ ) sum up to $16$, not $12$.
Test Cases:
Imperfect:
1,12,13,18,20,1000,33550335
Perfect:
6,28,496,8128,33550336,8589869056
Rules
- Your program doesn't have to complete the larger test cases, if there's memory or time constraints, but it should be theoretically able to if it were given more memory/time.
- Output can be two distinct and consistent values through any allowed output format. If it isn't immediately obvious what represents Truthy/Falsey, please make sure to specify in your answer.
- This means your values don't have to be literally Truthy/Falsey. Your Truthy output may evaluate to false in your language and vice-versa.
code-golf number decision-problem number-theory factoring
asked 1 hour ago
Jo KingJo King
24.6k357126
$endgroup$
Background:
The current Perfect Numbers challenge is rather flawed and complicated, since it asks you to output in a complex format involving the factors of the number. This is a purely decision-problem repost of the challenge.
Challenge
Given a positive integer through any standard input format, output whether it is not perfect.
A perfect number is a number that is equal to the sum of all its proper divisors (its positive divisors less than itself). For example, $6$ is a perfect number, since its divisors are $1,2,3$, which sum up to $6$, while $12$ is not a perfect number since its divisors ( $1,2,3,4,6$ ) sum up to $16$, not $12$.
Test Cases:
Imperfect:
1,12,13,18,20,1000,33550335
Perfect:
6,28,496,8128,33550336,8589869056
Rules
- Your program doesn't have to complete the larger test cases, if there's memory or time constraints, but it should be theoretically able to if it were given more memory/time.
- Output can be two distinct and consistent values through any allowed output format. If it isn't immediately obvious what represents Truthy/Falsey, please make sure to specify in your answer.
- This means your values don't have to be literally Truthy/Falsey. Your Truthy output may evaluate to false in your language and vice-versa.
code-golf number decision-problem number-theory factoring
code-golf number decision-problem number-theory factoring
asked 1 hour ago
Jo KingJo King
24.6k357126
asked 1 hour ago
Jo KingJo King
24.6k357126
edited 46 mins ago
Jo King
asked 1 hour ago
Jo KingJo King
24.6k357126
asked 1 hour ago
Jo KingJo King
24.6k357126
asked 1 hour ago
Jo KingJo King
24.6k357126
24.6k357126
$begingroup$
Wait, so truthy is for values that aren't perfect, and falsey is for values that are?
$endgroup$
– Esolanging Fruit
50 mins ago
$begingroup$
@EsolangingFruit Yes, though the actual output values don't really matter, so you can output true for perfect numbers if you wish
$endgroup$
– Jo King
48 mins ago
$begingroup$
Fair enough, but wording the challenge as "output whether it is not perfect" makes the test cases slightly confusing if you interpret "truthy" as meaning "values corresponding to true".
$endgroup$
– Esolanging Fruit
47 mins ago
$begingroup$
@EsolangingFruit Good point. I've renamed the test cases toImperfect/Perfectto make it clearer
$endgroup$
– Jo King
45 mins ago
add a comment |
$begingroup$
Wait, so truthy is for values that aren't perfect, and falsey is for values that are?
$endgroup$
– Esolanging Fruit
50 mins ago
$begingroup$
@EsolangingFruit Yes, though the actual output values don't really matter, so you can output true for perfect numbers if you wish
$endgroup$
– Jo King
48 mins ago
$begingroup$
Fair enough, but wording the challenge as "output whether it is not perfect" makes the test cases slightly confusing if you interpret "truthy" as meaning "values corresponding to true".
$endgroup$
– Esolanging Fruit
47 mins ago
$begingroup$
@EsolangingFruit Good point. I've renamed the test cases toImperfect/Perfectto make it clearer
$endgroup$
– Jo King
45 mins ago
$begingroup$
Wait, so truthy is for values that aren't perfect, and falsey is for values that are?
$endgroup$
– Esolanging Fruit
50 mins ago
$begingroup$
Wait, so truthy is for values that aren't perfect, and falsey is for values that are?
$endgroup$
– Esolanging Fruit
50 mins ago
$begingroup$
@EsolangingFruit Yes, though the actual output values don't really matter, so you can output true for perfect numbers if you wish
$endgroup$
– Jo King
48 mins ago
$begingroup$
@EsolangingFruit Yes, though the actual output values don't really matter, so you can output true for perfect numbers if you wish
$endgroup$
– Jo King
48 mins ago
$begingroup$
Fair enough, but wording the challenge as "output whether it is not perfect" makes the test cases slightly confusing if you interpret "truthy" as meaning "values corresponding to true".
$endgroup$
– Esolanging Fruit
47 mins ago
$begingroup$
Fair enough, but wording the challenge as "output whether it is not perfect" makes the test cases slightly confusing if you interpret "truthy" as meaning "values corresponding to true".
$endgroup$
– Esolanging Fruit
47 mins ago
$begingroup$
@EsolangingFruit Good point. I've renamed the test cases to
Imperfect/Perfect to make it clearer$endgroup$
– Jo King
45 mins ago
$begingroup$
@EsolangingFruit Good point. I've renamed the test cases to
Imperfect/Perfect to make it clearer$endgroup$
– Jo King
45 mins ago
add a comment |
4 Answers
4
active
oldest
votes
$begingroup$
Japt -!, 4 bytes
¥â¬x
For some reason ¦ doesnt work on tio so I need to use the -! flag and ¥ instead
Try it online!
answered 53 mins ago
Luis felipe De jesus MunozLuis felipe De jesus Munoz
5,60821670
$endgroup$
add a comment |
$begingroup$
R, 33 bytes
!2*(n=scan())-sum(which(!n%%1:n))
Try it online!
Returns TRUE for perfect numbers ans FALSE for imperfect ones.
answered 34 mins ago
GiuseppeGiuseppe
16.8k31052
$endgroup$
$begingroup$
What do the 2 !s in a row get you?
$endgroup$
– CT Hall
30 mins ago
$begingroup$
@CTHall I misread the spec; they originally mapped0(perfect) toFALSEand nonzero toTRUEbut I removed one of them to reverse the mapping. It's a useful golfing trick to cast fromnumerictological, often in conjunction withwhichor[.
$endgroup$
– Giuseppe
10 mins ago
add a comment |
$begingroup$
CJam, 17 bytes
ri_,(;{1$%!},:+=
Try it online!
answered 48 mins ago
Esolanging FruitEsolanging Fruit
8,50932674
$endgroup$
add a comment |
$begingroup$
Javascript, 62
n=>n==[...Array(n).keys()].filter(a=>n%a<1).reduce((a,b)=>a+b)
Explanation (although it's pretty simple)
n=> //return function that takes n
n== //and returns if n is equal to
[...Array(n).keys()] //an array [0..(n-1)]...
.filter(a=>n%a<1) //where all of the elements that are not divisors of n are taken out...
.reduce((a,b)=>a+b) //summed up
Thanks to Jo King for the improvement!
answered 52 mins ago
zeveezevee
22016
$endgroup$
$begingroup$
thanks! Added that in
$endgroup$
– zevee
44 mins ago
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Japt -!, 4 bytes
¥â¬x
For some reason ¦ doesnt work on tio so I need to use the -! flag and ¥ instead
Try it online!
answered 53 mins ago
Luis felipe De jesus MunozLuis felipe De jesus Munoz
5,60821670
$endgroup$
add a comment |
$begingroup$
Japt -!, 4 bytes
¥â¬x
For some reason ¦ doesnt work on tio so I need to use the -! flag and ¥ instead
Try it online!
answered 53 mins ago
Luis felipe De jesus MunozLuis felipe De jesus Munoz
5,60821670
$endgroup$
add a comment |
$begingroup$
Japt -!, 4 bytes
¥â¬x
For some reason ¦ doesnt work on tio so I need to use the -! flag and ¥ instead
Try it online!
answered 53 mins ago
Luis felipe De jesus MunozLuis felipe De jesus Munoz
5,60821670
$endgroup$
Japt -!, 4 bytes
¥â¬x
For some reason ¦ doesnt work on tio so I need to use the -! flag and ¥ instead
Try it online!
answered 53 mins ago
Luis felipe De jesus MunozLuis felipe De jesus Munoz
5,60821670
edited 48 mins ago
answered 53 mins ago
Luis felipe De jesus MunozLuis felipe De jesus Munoz
5,60821670
answered 53 mins ago
Luis felipe De jesus MunozLuis felipe De jesus Munoz
5,60821670
answered 53 mins ago
Luis felipe De jesus MunozLuis felipe De jesus Munoz
5,60821670
5,60821670
add a comment |
add a comment |
$begingroup$
R, 33 bytes
!2*(n=scan())-sum(which(!n%%1:n))
Try it online!
Returns TRUE for perfect numbers ans FALSE for imperfect ones.
answered 34 mins ago
GiuseppeGiuseppe
16.8k31052
$endgroup$
$begingroup$
What do the 2 !s in a row get you?
$endgroup$
– CT Hall
30 mins ago
$begingroup$
@CTHall I misread the spec; they originally mapped0(perfect) toFALSEand nonzero toTRUEbut I removed one of them to reverse the mapping. It's a useful golfing trick to cast fromnumerictological, often in conjunction withwhichor[.
$endgroup$
– Giuseppe
10 mins ago
add a comment |
$begingroup$
R, 33 bytes
!2*(n=scan())-sum(which(!n%%1:n))
Try it online!
Returns TRUE for perfect numbers ans FALSE for imperfect ones.
answered 34 mins ago
GiuseppeGiuseppe
16.8k31052
$endgroup$
$begingroup$
What do the 2 !s in a row get you?
$endgroup$
– CT Hall
30 mins ago
$begingroup$
@CTHall I misread the spec; they originally mapped0(perfect) toFALSEand nonzero toTRUEbut I removed one of them to reverse the mapping. It's a useful golfing trick to cast fromnumerictological, often in conjunction withwhichor[.
$endgroup$
– Giuseppe
10 mins ago
add a comment |
$begingroup$
R, 33 bytes
!2*(n=scan())-sum(which(!n%%1:n))
Try it online!
Returns TRUE for perfect numbers ans FALSE for imperfect ones.
answered 34 mins ago
GiuseppeGiuseppe
16.8k31052
$endgroup$
R, 33 bytes
!2*(n=scan())-sum(which(!n%%1:n))
Try it online!
Returns TRUE for perfect numbers ans FALSE for imperfect ones.
answered 34 mins ago
GiuseppeGiuseppe
16.8k31052
answered 34 mins ago
GiuseppeGiuseppe
16.8k31052
answered 34 mins ago
GiuseppeGiuseppe
16.8k31052
answered 34 mins ago
GiuseppeGiuseppe
16.8k31052
16.8k31052
$begingroup$
What do the 2 !s in a row get you?
$endgroup$
– CT Hall
30 mins ago
$begingroup$
@CTHall I misread the spec; they originally mapped0(perfect) toFALSEand nonzero toTRUEbut I removed one of them to reverse the mapping. It's a useful golfing trick to cast fromnumerictological, often in conjunction withwhichor[.
$endgroup$
– Giuseppe
10 mins ago
add a comment |
$begingroup$
What do the 2 !s in a row get you?
$endgroup$
– CT Hall
30 mins ago
$begingroup$
@CTHall I misread the spec; they originally mapped0(perfect) toFALSEand nonzero toTRUEbut I removed one of them to reverse the mapping. It's a useful golfing trick to cast fromnumerictological, often in conjunction withwhichor[.
$endgroup$
– Giuseppe
10 mins ago
$begingroup$
What do the 2 !s in a row get you?
$endgroup$
– CT Hall
30 mins ago
$begingroup$
What do the 2 !s in a row get you?
$endgroup$
– CT Hall
30 mins ago
$begingroup$
@CTHall I misread the spec; they originally mapped
0 (perfect) to FALSE and nonzero to TRUE but I removed one of them to reverse the mapping. It's a useful golfing trick to cast from numeric to logical, often in conjunction with which or [.$endgroup$
– Giuseppe
10 mins ago
$begingroup$
@CTHall I misread the spec; they originally mapped
0 (perfect) to FALSE and nonzero to TRUE but I removed one of them to reverse the mapping. It's a useful golfing trick to cast from numeric to logical, often in conjunction with which or [.$endgroup$
– Giuseppe
10 mins ago
add a comment |
$begingroup$
CJam, 17 bytes
ri_,(;{1$%!},:+=
Try it online!
answered 48 mins ago
Esolanging FruitEsolanging Fruit
8,50932674
$endgroup$
add a comment |
$begingroup$
CJam, 17 bytes
ri_,(;{1$%!},:+=
Try it online!
answered 48 mins ago
Esolanging FruitEsolanging Fruit
8,50932674
$endgroup$
add a comment |
$begingroup$
CJam, 17 bytes
ri_,(;{1$%!},:+=
Try it online!
answered 48 mins ago
Esolanging FruitEsolanging Fruit
8,50932674
$endgroup$
CJam, 17 bytes
ri_,(;{1$%!},:+=
Try it online!
answered 48 mins ago
Esolanging FruitEsolanging Fruit
8,50932674
answered 48 mins ago
Esolanging FruitEsolanging Fruit
8,50932674
answered 48 mins ago
Esolanging FruitEsolanging Fruit
8,50932674
answered 48 mins ago
Esolanging FruitEsolanging Fruit
8,50932674
8,50932674
add a comment |
add a comment |
$begingroup$
Javascript, 62
n=>n==[...Array(n).keys()].filter(a=>n%a<1).reduce((a,b)=>a+b)
Explanation (although it's pretty simple)
n=> //return function that takes n
n== //and returns if n is equal to
[...Array(n).keys()] //an array [0..(n-1)]...
.filter(a=>n%a<1) //where all of the elements that are not divisors of n are taken out...
.reduce((a,b)=>a+b) //summed up
Thanks to Jo King for the improvement!
answered 52 mins ago
zeveezevee
22016
$endgroup$
$begingroup$
thanks! Added that in
$endgroup$
– zevee
44 mins ago
add a comment |
$begingroup$
Javascript, 62
n=>n==[...Array(n).keys()].filter(a=>n%a<1).reduce((a,b)=>a+b)
Explanation (although it's pretty simple)
n=> //return function that takes n
n== //and returns if n is equal to
[...Array(n).keys()] //an array [0..(n-1)]...
.filter(a=>n%a<1) //where all of the elements that are not divisors of n are taken out...
.reduce((a,b)=>a+b) //summed up
Thanks to Jo King for the improvement!
answered 52 mins ago
zeveezevee
22016
$endgroup$
$begingroup$
thanks! Added that in
$endgroup$
– zevee
44 mins ago
add a comment |
$begingroup$
Javascript, 62
n=>n==[...Array(n).keys()].filter(a=>n%a<1).reduce((a,b)=>a+b)
Explanation (although it's pretty simple)
n=> //return function that takes n
n== //and returns if n is equal to
[...Array(n).keys()] //an array [0..(n-1)]...
.filter(a=>n%a<1) //where all of the elements that are not divisors of n are taken out...
.reduce((a,b)=>a+b) //summed up
Thanks to Jo King for the improvement!
answered 52 mins ago
zeveezevee
22016
$endgroup$
Javascript, 62
n=>n==[...Array(n).keys()].filter(a=>n%a<1).reduce((a,b)=>a+b)
Explanation (although it's pretty simple)
n=> //return function that takes n
n== //and returns if n is equal to
[...Array(n).keys()] //an array [0..(n-1)]...
.filter(a=>n%a<1) //where all of the elements that are not divisors of n are taken out...
.reduce((a,b)=>a+b) //summed up
Thanks to Jo King for the improvement!
answered 52 mins ago
zeveezevee
22016
edited 44 mins ago
answered 52 mins ago
zeveezevee
22016
answered 52 mins ago
zeveezevee
22016
answered 52 mins ago
zeveezevee
22016
22016
$begingroup$
thanks! Added that in
$endgroup$
– zevee
44 mins ago
add a comment |
$begingroup$
thanks! Added that in
$endgroup$
– zevee
44 mins ago
$begingroup$
thanks! Added that in
$endgroup$
– zevee
44 mins ago
$begingroup$
thanks! Added that in
$endgroup$
– zevee
44 mins ago
add a comment |
If this is an answer to a challenge…
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Explanations of your answer make it more interesting to read and are very much encouraged.…Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.
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…Please make sure to answer the question and provide sufficient detail.
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Wait, so truthy is for values that aren't perfect, and falsey is for values that are?
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– Esolanging Fruit
50 mins ago
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@EsolangingFruit Yes, though the actual output values don't really matter, so you can output true for perfect numbers if you wish
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– Jo King
48 mins ago
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Fair enough, but wording the challenge as "output whether it is not perfect" makes the test cases slightly confusing if you interpret "truthy" as meaning "values corresponding to true".
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– Esolanging Fruit
47 mins ago
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@EsolangingFruit Good point. I've renamed the test cases to
Imperfect/Perfectto make it clearer$endgroup$
– Jo King
45 mins ago