Sfdwhf

Did any laptop computers have a built-in 5 1/4 inch floppy drive?

Falsification in Math vs Science

What information about me do stores get via my credit card?

How do you keep chess fun when your opponent constantly beats you?

writing variables above the numbers in tikz picture

Deal with toxic manager when you can't quit

How to notate time signature switching consistently every measure

What is the most efficient way to store a numeric range?

RequirePermission not working

What is the motivation for a law requiring 2 parties to consent for recording a conversation

Can we generate random numbers using irrational numbers like π and e?

How can I add encounters in the Lost Mine of Phandelver campaign without giving PCs too much XP?

Why not take a picture of a closer black hole?

Alternative to の

Is it ok to offer lower paid work as a trial period before negotiating for a full-time job?

Did Scotland spend $250,000 for the slogan "Welcome to Scotland"?

Worn-tile Scrabble

Does HR tell a hiring manager about salary negotiations?

Did the UK government pay "millions and millions of dollars" to try to snag Julian Assange?

How to add class in ko template in magento2

Why don't hard Brexiteers insist on a hard border to prevent illegal immigration after Brexit?

What do these terms in Caesar's Gallic Wars mean?

"as much details as you can remember"

Why is the maximum length of OpenWrt’s root password 8 characters?

How to run a script automatically in linux?

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

4

0

I use linux command line and I'm a beginner with it.
I've created two files, test.sh and test.log.
the process is any output going to test.log and i get it successfully the output in test.log.
I want to run a script automatically every 5 seconds and write only if there is any change with the .sh file.

test.sh contains :

#!/bin/bash

while [ true ] ;

do

echo "" date and Time >> test.log

date +%x_r >> test.log

lsusb >> test.log



sleep 5;

done

My question: Is there any way to run it automatically and only append the new change in the file with the new date? for example if anyone insert USB device into my machine it will append it with the new date into the existing log file it.

bash scripts

share|improve this question

edited Nov 16 '16 at 15:49

amc

4,81462746

asked Nov 16 '16 at 15:17

GhassanGhassan

265

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This seems like an unnecessarily complicated way to do it. You should check the manpages for cron
  
  – Simon Aronsson
  Nov 16 '16 at 17:25
  

  
  
  
  

add a comment | 

4

0

I use linux command line and I'm a beginner with it.
I've created two files, test.sh and test.log.
the process is any output going to test.log and i get it successfully the output in test.log.
I want to run a script automatically every 5 seconds and write only if there is any change with the .sh file.

test.sh contains :

#!/bin/bash

while [ true ] ;

do

echo "" date and Time >> test.log

date +%x_r >> test.log

lsusb >> test.log



sleep 5;

done

My question: Is there any way to run it automatically and only append the new change in the file with the new date? for example if anyone insert USB device into my machine it will append it with the new date into the existing log file it.

bash scripts

share|improve this question

edited Nov 16 '16 at 15:49

amc

4,81462746

asked Nov 16 '16 at 15:17

GhassanGhassan

265

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This seems like an unnecessarily complicated way to do it. You should check the manpages for cron
  
  – Simon Aronsson
  Nov 16 '16 at 17:25
  

  
  
  
  

add a comment | 

I use linux command line and I'm a beginner with it.
I've created two files, test.sh and test.log.
the process is any output going to test.log and i get it successfully the output in test.log.
I want to run a script automatically every 5 seconds and write only if there is any change with the .sh file.

test.sh contains :

#!/bin/bash

while [ true ] ;

do

echo "" date and Time >> test.log

date +%x_r >> test.log

lsusb >> test.log



sleep 5;

done

My question: Is there any way to run it automatically and only append the new change in the file with the new date? for example if anyone insert USB device into my machine it will append it with the new date into the existing log file it.

bash scripts

share|improve this question

edited Nov 16 '16 at 15:49

amc

4,81462746

asked Nov 16 '16 at 15:17

GhassanGhassan

265

#!/bin/bash

while [ true ] ;

do

echo "" date and Time >> test.log

date +%x_r >> test.log

lsusb >> test.log



sleep 5;

done

share|improve this question

edited Nov 16 '16 at 15:49

amc

4,81462746

asked Nov 16 '16 at 15:17

GhassanGhassan

265

share|improve this question

edited Nov 16 '16 at 15:49

amc

4,81462746

asked Nov 16 '16 at 15:17

GhassanGhassan

265

edited Nov 16 '16 at 15:49

amc

4,81462746

edited Nov 16 '16 at 15:49

amc

4,81462746

asked Nov 16 '16 at 15:17

GhassanGhassan

265

asked Nov 16 '16 at 15:17

GhassanGhassan

265

2 Answers
2

active

oldest

votes

1

This should work, it stores the last output of lsusb in $lastoutput and appends if they're if not equal

#!/bin/bash

while [ true ] 

do

    currentoutput="$(lsusb)"

    if [ "$currentoutput" != "$lastoutput" ]

    then

        echo "" date and Time >> test.log

        date +%x_r >> test.log

        lastoutput="$(lsusb)"

        lsusb >> test.log

    fi

    sleep 5

done

share|improve this answer

edited Nov 16 '16 at 23:53

answered Nov 16 '16 at 16:29

Evan ChenEvan Chen

74449

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks , but in this way it will not save the new change in .log file ,, i try it and it's running in the terminal not in the .log file
  
  – Ghassan
  Nov 16 '16 at 18:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes its in the terminal , but the result (new change) should go to .log file but does not .
  
  – Ghassan
  Nov 16 '16 at 20:55
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Ghassan does the user running the script have enough permissions to write in the test.log file? Could it be that maybe you created the file as root and is now running it as your regular user?
  
  – IanC
  Nov 16 '16 at 23:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  My apologies, I did not realize that the code doesn't work (I was typing on my phone and I wasn't able to test it). I fixed it now, it should work
  
  – Evan Chen
  Nov 16 '16 at 23:54
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Ghassan can you try the new code?
  
  – Evan Chen
  Nov 17 '16 at 0:07
  

  
  
  
  

 | 
show 3 more comments

-1

You have to:

• put your file in /etc/init.d directory


• make your sh file executable (use the chmod +x command)

If it doesn't work properly, create a symlink of your file to /etc/rc.d/:

ln -s /etc/init.d/test.sh /etc/rc.d/ 

May that helps :)

share|improve this answer

edited Nov 16 '16 at 23:05

SYN

556212

answered Nov 16 '16 at 17:25

Dodi lilaDodi lila

6116

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The question asks how to automatically detect change, not how to start on boot
  
  – Evan Chen
  Nov 16 '16 at 18:19
  

  
  
  
  

add a comment | 

Your Answer

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "89"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2faskubuntu.com%2fquestions%2f850143%2fhow-to-run-a-script-automatically-in-linux%23new-answer', 'question_page');
}
);

Post as a guest

Name

Email

Required, but never shown

1

This should work, it stores the last output of lsusb in $lastoutput and appends if they're if not equal

#!/bin/bash

while [ true ] 

do

    currentoutput="$(lsusb)"

    if [ "$currentoutput" != "$lastoutput" ]

    then

        echo "" date and Time >> test.log

        date +%x_r >> test.log

        lastoutput="$(lsusb)"

        lsusb >> test.log

    fi

    sleep 5

done

share|improve this answer

edited Nov 16 '16 at 23:53

answered Nov 16 '16 at 16:29

Evan ChenEvan Chen

74449

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks , but in this way it will not save the new change in .log file ,, i try it and it's running in the terminal not in the .log file
  
  – Ghassan
  Nov 16 '16 at 18:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes its in the terminal , but the result (new change) should go to .log file but does not .
  
  – Ghassan
  Nov 16 '16 at 20:55
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Ghassan does the user running the script have enough permissions to write in the test.log file? Could it be that maybe you created the file as root and is now running it as your regular user?
  
  – IanC
  Nov 16 '16 at 23:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  My apologies, I did not realize that the code doesn't work (I was typing on my phone and I wasn't able to test it). I fixed it now, it should work
  
  – Evan Chen
  Nov 16 '16 at 23:54
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Ghassan can you try the new code?
  
  – Evan Chen
  Nov 17 '16 at 0:07
  

  
  
  
  

 | 
show 3 more comments

1

This should work, it stores the last output of lsusb in $lastoutput and appends if they're if not equal

#!/bin/bash

while [ true ] 

do

    currentoutput="$(lsusb)"

    if [ "$currentoutput" != "$lastoutput" ]

    then

        echo "" date and Time >> test.log

        date +%x_r >> test.log

        lastoutput="$(lsusb)"

        lsusb >> test.log

    fi

    sleep 5

done

share|improve this answer

edited Nov 16 '16 at 23:53

answered Nov 16 '16 at 16:29

Evan ChenEvan Chen

74449

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks , but in this way it will not save the new change in .log file ,, i try it and it's running in the terminal not in the .log file
  
  – Ghassan
  Nov 16 '16 at 18:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes its in the terminal , but the result (new change) should go to .log file but does not .
  
  – Ghassan
  Nov 16 '16 at 20:55
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Ghassan does the user running the script have enough permissions to write in the test.log file? Could it be that maybe you created the file as root and is now running it as your regular user?
  
  – IanC
  Nov 16 '16 at 23:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  My apologies, I did not realize that the code doesn't work (I was typing on my phone and I wasn't able to test it). I fixed it now, it should work
  
  – Evan Chen
  Nov 16 '16 at 23:54
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Ghassan can you try the new code?
  
  – Evan Chen
  Nov 17 '16 at 0:07
  

  
  
  
  

 | 
show 3 more comments

This should work, it stores the last output of lsusb in $lastoutput and appends if they're if not equal

#!/bin/bash

while [ true ] 

do

    currentoutput="$(lsusb)"

    if [ "$currentoutput" != "$lastoutput" ]

    then

        echo "" date and Time >> test.log

        date +%x_r >> test.log

        lastoutput="$(lsusb)"

        lsusb >> test.log

    fi

    sleep 5

done

share|improve this answer

edited Nov 16 '16 at 23:53

answered Nov 16 '16 at 16:29

Evan ChenEvan Chen

74449

#!/bin/bash

while [ true ] 

do

    currentoutput="$(lsusb)"

    if [ "$currentoutput" != "$lastoutput" ]

    then

        echo "" date and Time >> test.log

        date +%x_r >> test.log

        lastoutput="$(lsusb)"

        lsusb >> test.log

    fi

    sleep 5

done

share|improve this answer

edited Nov 16 '16 at 23:53

answered Nov 16 '16 at 16:29

Evan ChenEvan Chen

74449

answered Nov 16 '16 at 16:29

Evan ChenEvan Chen

74449

answered Nov 16 '16 at 16:29

Evan ChenEvan Chen

74449

-1

You have to:

• put your file in /etc/init.d directory


• make your sh file executable (use the chmod +x command)

If it doesn't work properly, create a symlink of your file to /etc/rc.d/:

ln -s /etc/init.d/test.sh /etc/rc.d/ 

May that helps :)

share|improve this answer

edited Nov 16 '16 at 23:05

SYN

556212

answered Nov 16 '16 at 17:25

Dodi lilaDodi lila

6116

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The question asks how to automatically detect change, not how to start on boot
  
  – Evan Chen
  Nov 16 '16 at 18:19
  

  
  
  
  

add a comment | 

-1

You have to:

• put your file in /etc/init.d directory


• make your sh file executable (use the chmod +x command)

If it doesn't work properly, create a symlink of your file to /etc/rc.d/:

ln -s /etc/init.d/test.sh /etc/rc.d/ 

May that helps :)

share|improve this answer

edited Nov 16 '16 at 23:05

SYN

556212

answered Nov 16 '16 at 17:25

Dodi lilaDodi lila

6116

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The question asks how to automatically detect change, not how to start on boot
  
  – Evan Chen
  Nov 16 '16 at 18:19
  

  
  
  
  

add a comment | 

You have to:

• put your file in /etc/init.d directory


• make your sh file executable (use the chmod +x command)

If it doesn't work properly, create a symlink of your file to /etc/rc.d/:

ln -s /etc/init.d/test.sh /etc/rc.d/ 

May that helps :)

share|improve this answer

edited Nov 16 '16 at 23:05

SYN

556212

answered Nov 16 '16 at 17:25

Dodi lilaDodi lila

6116

ln -s /etc/init.d/test.sh /etc/rc.d/ 

share|improve this answer

edited Nov 16 '16 at 23:05

SYN

556212

answered Nov 16 '16 at 17:25

Dodi lilaDodi lila

6116

edited Nov 16 '16 at 23:05

SYN

556212

edited Nov 16 '16 at 23:05

SYN

556212

answered Nov 16 '16 at 17:25

Dodi lilaDodi lila

6116

answered Nov 16 '16 at 17:25

Dodi lilaDodi lila

6116