bash function without argumentsbash: [: too many arguments?Change Gsetting with script on...
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bash function without arguments
bash: [: too many arguments?Change Gsetting with script on Logoutalias/function with command line argumentsEcho script arguments from functionBash Function Oblivionhow to fix my keyboard after a bash script messed it upprocessing arguments with bash functionBash Command Arguments ${…}Bash randomization function errorHow to pass arguments from one function to another function in bash scripting?
I am analyzing the following script (init script for ptpd2 deamon):
#!/bin/sh
#
# Start ptpd2
#
case "$1" in
start)
printf "Starting ptpd2: "
start-stop-daemon -S -q -x /usr/sbin/ptpd2 -- -g -i eth0 -s
if [ $? != 0 ]; then
echo "FAILED"
exit 1
else
echo "OK"
fi
;;
stop)
printf "Stopping ptpd2: "
start-stop-daemon -K -q -x /usr/sbin/ptpd2
echo "OK"
;;
restart|reload)
;;
*)
echo "Usage: $0 {start|stop|restart}"
exit 1
esac
exit $?
What does start), stop) mean? What kind of constraction is this? A function without arguments maybe?
bash
add a comment |
I am analyzing the following script (init script for ptpd2 deamon):
#!/bin/sh
#
# Start ptpd2
#
case "$1" in
start)
printf "Starting ptpd2: "
start-stop-daemon -S -q -x /usr/sbin/ptpd2 -- -g -i eth0 -s
if [ $? != 0 ]; then
echo "FAILED"
exit 1
else
echo "OK"
fi
;;
stop)
printf "Stopping ptpd2: "
start-stop-daemon -K -q -x /usr/sbin/ptpd2
echo "OK"
;;
restart|reload)
;;
*)
echo "Usage: $0 {start|stop|restart}"
exit 1
esac
exit $?
What does start), stop) mean? What kind of constraction is this? A function without arguments maybe?
bash
part of thecase
structure, started withcase
and ending at theesac
(case backwards) line. It controls execution by the "$1" ...
– guiverc
38 secs ago
add a comment |
I am analyzing the following script (init script for ptpd2 deamon):
#!/bin/sh
#
# Start ptpd2
#
case "$1" in
start)
printf "Starting ptpd2: "
start-stop-daemon -S -q -x /usr/sbin/ptpd2 -- -g -i eth0 -s
if [ $? != 0 ]; then
echo "FAILED"
exit 1
else
echo "OK"
fi
;;
stop)
printf "Stopping ptpd2: "
start-stop-daemon -K -q -x /usr/sbin/ptpd2
echo "OK"
;;
restart|reload)
;;
*)
echo "Usage: $0 {start|stop|restart}"
exit 1
esac
exit $?
What does start), stop) mean? What kind of constraction is this? A function without arguments maybe?
bash
I am analyzing the following script (init script for ptpd2 deamon):
#!/bin/sh
#
# Start ptpd2
#
case "$1" in
start)
printf "Starting ptpd2: "
start-stop-daemon -S -q -x /usr/sbin/ptpd2 -- -g -i eth0 -s
if [ $? != 0 ]; then
echo "FAILED"
exit 1
else
echo "OK"
fi
;;
stop)
printf "Stopping ptpd2: "
start-stop-daemon -K -q -x /usr/sbin/ptpd2
echo "OK"
;;
restart|reload)
;;
*)
echo "Usage: $0 {start|stop|restart}"
exit 1
esac
exit $?
What does start), stop) mean? What kind of constraction is this? A function without arguments maybe?
bash
bash
asked 3 mins ago
AndyAndy
11
11
part of thecase
structure, started withcase
and ending at theesac
(case backwards) line. It controls execution by the "$1" ...
– guiverc
38 secs ago
add a comment |
part of thecase
structure, started withcase
and ending at theesac
(case backwards) line. It controls execution by the "$1" ...
– guiverc
38 secs ago
part of the
case
structure, started with case
and ending at the esac
(case backwards) line. It controls execution by the "$1" ...– guiverc
38 secs ago
part of the
case
structure, started with case
and ending at the esac
(case backwards) line. It controls execution by the "$1" ...– guiverc
38 secs ago
add a comment |
0
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part of the
case
structure, started withcase
and ending at theesac
(case backwards) line. It controls execution by the "$1" ...– guiverc
38 secs ago